Question

我试图在对象中找到一个值，但我似乎无法得到正在做的事情。也许我错了。我有两个对象，我想要做的是删除不在第二个对象中的行。这是对象1：

    Array ( 
    [idCategory1] => 1 
    [idCategory2] => 2 
    [idCategory4] => 4 
)

这是对象2：

 Array ( 
    [0] => Array ( 
        [CategoriesProvider] => Array ( 
            [id] => 28 
            [provider_id] => 2 
            [category_id] => 1 
            [created] => 2015-03-13 20:25:17 
            [modified] => 2015-03-13 20:25:17 
        ) 
    ) 
    [1] => Array ( 
        [CategoriesProvider] => Array ( 
            [id] => 29 
            [provider_id] => 2 
            [category_id] => 2 
            [created] => 2015-03-13 20:25:17 
            [modified] => 2015-03-13 20:25:17 
        ) 
    ) 
    [2] => Array ( 
        [CategoriesProvider] => Array ( 
            [id] => 30 
            [provider_id] => 2 
            [category_id] => 4 
            [created] => 2015-03-13 20:25:17 
            [modified] => 2015-03-13 20:25:17 
        ) 
    ) 
)

这是我删除对象2中不在对象1中的行的代码。

 foreach ($CategoriesOfProvider as $key ) {
    if(isset($CategoriesProvider['CategoriesProvider']->$key['CategoriesProvider']['category_id'])) {

    }  else {
        $this->User->Provider->CategoriesProvider->id = $key['CategoriesProvider']['id'];
        //$this->request->allowMethod('post', 'delete');
        if ($this->User->Provider->CategoriesProvider->delete()) {

        } else {
            $this->Session->setFlash(
                '<button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button> No se pudo borrar la relacion producto - categoría.',
                'default',
                array('class' => 'alert alert-danger alert-dismissible', 'type' => 'alert')
            );
        }
    }
}

$CategoriesOfProvider是对象2而$CategoriesProvider是对象1.所以我试图使用isset来查找对象2中的id是否在对象1的值中。我认为我使用isset错误。或者还有另一种方式吗？我想也许可以针对对象1的每个值运行它。这会更好吗？

提前感谢您的帮助。

Answer 1

好的，我发现了怎么做。我停止使用isset而是使用另一个foreach并浏览对象1中的所有值。如果找不到，那么我删除了额外的类别。这是代码。

$this->User->Provider->CategoriesProvider->recursive = -1;
$CategoriesOfProvider = $this->User->Provider->CategoriesProvider->find('all', array( 'conditions'=> array('CategoriesProvider.provider_id' => $provider_id ) ) );

//echo print_r($CategoriesProvider);
//return print_r($CategoriesOfProvider);

foreach ($CategoriesOfProvider as $key ) {
    $found = false;
    //if(isset($CategoriesProvider['CategoriesProvider']->$key['CategoriesProvider']['category_id'])) {
    foreach ($CategoriesProvider as $key1 => $value) {
        if($key['CategoriesProvider']['category_id'] == $value) {
            $found = true;
        }  
    }

    if($found) {

    }  else {
        $this->User->Provider->CategoriesProvider->id = $key['CategoriesProvider']['id'];
        //$this->request->allowMethod('post', 'delete');
        if ($this->User->Provider->CategoriesProvider->delete()) {

        } else {
            $this->Session->setFlash(
                '<button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">&times;</span></button> No se pudo borrar la relacion producto - categoría.',
                'default',
                array('class' => 'alert alert-danger alert-dismissible', 'type' => 'alert')
            );
        }
    }

}

我希望它有助于某人：P

在CakePHP对象中查找值

1 个答案: