Question

我有一个程序逻辑问题，如何获取服务器上所有文件夹的列表：

让我们说，我有一个如下文件夹结构，我想获得其中所有文件夹的列表：

！[在此处输入图片说明] [1]

＆＃13;

String rootDirectory = “Root”; 
CmdClient client = null; 
client.connect("demo.asperasoft.com", "asperaweb", "demoaspera", 22);

// This method gives list of files inside param folder CmdReplyFile cmdfiles=client.execLs(rootDirectory);

//this method gives a list of files 
File[] fileObjects = cmdfiles.getFileList();

//this method gives file count 
int fileCount= cmdfiles.getFileCount();

＆＃13;

此处的文件类不是Java文件类。现在，当我试图打印所有文件夹的列表时，它只是给了我：

α Beta版伽马

＆＃13;

private void getFolderList(String rootDirectory) throws IOException, CmdClientException {
        CmdReplyFile cmdfiles=client.execLs(rootDirectory);
        File[] fileObjects = cmdfiles.getFileList();
        for (File fileObject : fileObjects) {
            if (fileObject.isDirectory()) {
                System.out.println(fileObject.getName());
                getFolderList(fileObject.getName());
            }
        }

＆＃13;

请提出可能的逻辑。

Answer 1

谢谢Kartic！我能用你的解决方案做到这一点：

public void getListOfFolders(String rootPath) throws IOException, CmdClientException {
    List<String> folders = new LinkedList<String>();
    folders.add(rootPath);
    getFolders(rootPath, folders);

    for (String items : folders){
        System.out.println("Folders: "+items.toString());
    }
}

public void getFolders(String directoryName, List<String> folders) throws IOException, CmdClientException {
    CmdReplyFile cmdfiles=client.execLs(directoryName);
    File[] fileObjects = cmdfiles.getFileList();
    String dirStructure=folders.get(folders.size()-1).toString();
    for (File file : fileObjects) {
        if (file.isDirectory()) {
            String folderPath=dirStructure+file.getName()+"/";
            folders.add(folderPath);
            getFolders(folderPath, folders);
        }
    }
}

Answer 2

我希望以下代码能满足您的要求：

public void getListOfFolders(String rootPath) {
    List<String> folders = new LinkedList<String>();
    getFolders(rootPath, folders);
    // Now folders got everything you need.
}

public void getFolders(String directoryName, List<String> folders) {
    File directory = new File(directoryName);
    File[] fList = directory.listFiles();
    for (File file : fList) {
        if (file.isDirectory()) {
            folders.add(file.getAbsolutePath());
            getFolders(file.getAbsolutePath(), folders);
        }
    }
}

获取所有子文件夹的列表

2 个答案: