Question

我有一个文章列表，每篇文章都属于一个部分。

class Section(models.Model):
  name = models.CharField(max_length=200)

  def __unicode__(self):
    return self.name

class Article(models.Model):
  section = models.ForeignKey(Section)
  headline = models.CharField(max_length=200)
  # ...

我想显示按章节分组的文章。

Sponsorships, Advertising & Marketing
1. Nike To Outfit All 18 Univ. Of Memphis Athletic Teams
2. Phil Jackson Questions Harrah's Signage At New Orleans Arena
3. Puma Hires N.Y.-Based Ad Agency Droga5 To Lead Global Account
4. Pizza Patrón To Replace Pizza Hut As AAC Exclusive Provider
5. Marketplace Roundup

Sports Media
6. Many Patriots Fans In New England Will Not See Tonight's Game
7. ESPN Ombudsman Says Net Should Have Clarified Holtz Situation
8. EA Sports To Debut Fitness Title For Nintendo Wii In Spring '09
9. Blog Hound: Rockets-Suns Scuffle Today's No.1 Topic
10. Media Notes

Leagues & Governing Bodies
11. DEI, Chip Ganassi Racing To Merge Into Four-Car Sprint Cup Team
12. NASCAR Roundtable Part II: New Strategies, Cutbacks Discussed
13. Average Ticket Price For NFL Playoff Games To Drop By 10%

我想出了如何使用Django的模板系统来完成大部分工作。

{% regroup articles by section as articles_by_section %}

{% for article in articles_by_section %}    
    <h4>{{ article.grouper }}</h4>
    <ul>
    {% for item in article.list %}  
        <li>{{ forloop.counter }}. {{ item.headline }}</li>
    {% endfor %}
    </ul>
{% endfor %}

我无法弄清楚如何做数字。上面的代码对Sports Media 1-5中的文章进行了编号，而不是6-10。有什么建议吗？

Answer 1

根据Jeb在评论中的建议，我创建了一个custom template tag。

我将{{ forloop.counter }}替换为{% counter %}，这是一个标记，只显示它被调用的次数。

这是我的计数器代码的代码。

class CounterNode(template.Node):

  def __init__(self):
    self.count = 0

  def render(self, context):
    self.count += 1
    return self.count

@register.tag
def counter(parser, token):
  return CounterNode()

Answer 2

这不是很整洁，但可能适合某人：

{% for article in articles %}        
   {% ifchanged article.section %}
      {% if not forloop.first %}</ul>{% endif %}
      <h4>{{article.section}}</h4>
      <ul>
   {% endifchanged %}
          <li>{{forloop.counter}}. {{ article.headline }}</li>
   {% if forloop.last %}</ul>{% endif %}
{% endfor %}

Answer 3

我认为你可以在内部循环中使用forloop.parentloop.counter来实现你所追求的编号。

Answer 4

您可以使用有序列表而不是无序列表：

{% regroup articles by section as articles_by_section %}

<ol>
{% for article in articles_by_section %}        
    <h4>{{ article.grouper }}</h4>
    {% for item in article.list %}  
        <li>{{ item.headline }}</li>
    {% endfor %}
{% endfor %}
</ol>

Django模板系统：如何解决这种循环/分组/计数？

4 个答案: