我不知道如何将Vec<i32>
转换为&[u8]
切片。
fn main() {
let v: Vec<i32> = vec![1; 100_000_000];
let v_bytes: &[u8] = /* ... */;
}
我想在文件中写一个大的Vec<i32>
,以便我以后可以阅读它。
答案 0 :(得分:9)
您可以使用std::slice::from_raw_parts
:
let v_bytes: &[u8] = unsafe {
std::slice::from_raw_parts(
v.as_ptr() as *const u8,
v.len() * std::mem::size_of::<i32>(),
)
};
根据对此答案的评论,您应该将此代码包装在一个函数中并使返回值借用输入,以便您尽可能使用借用检查器:
fn as_u8_slice(v: &[i32]) -> &[u8] {
unsafe {
std::slice::from_raw_parts(
v.as_ptr() as *const u8,
v.len() * std::mem::size_of::<i32>(),
)
}
}
答案 1 :(得分:5)
我拿了@swizards answer然后用它跑了一下以获得硬币的另一面 - 读回矢量:
use std::fs::File;
use std::io::{Read, Write};
use std::{mem, slice};
fn as_u8_slice(v: &[i32]) -> &[u8] {
let element_size = mem::size_of::<i32>();
unsafe { slice::from_raw_parts(v.as_ptr() as *const u8, v.len() * element_size) }
}
fn from_u8(v: Vec<u8>) -> Vec<i32> {
let data = v.as_ptr();
let len = v.len();
let capacity = v.capacity();
let element_size = mem::size_of::<i32>();
// Make sure we have a proper amount of capacity (may be overkill)
assert_eq!(capacity % element_size, 0);
// Make sure we are going to read a full chunk of stuff
assert_eq!(len % element_size, 0);
unsafe {
// Don't allow the current vector to be dropped
// (which would invalidate the memory)
mem::forget(v);
Vec::from_raw_parts(
data as *mut i32,
len / element_size,
capacity / element_size,
)
}
}
fn do_write(filename: &str, v: &[i32]) {
let mut f = File::create(filename).unwrap();
f.write_all(as_u8_slice(v)).unwrap();
}
fn do_read(filename: &str) -> Vec<i32> {
let mut f = File::open(filename).unwrap();
let mut bytes = Vec::new();
f.read_to_end(&mut bytes).unwrap();
from_u8(bytes)
}
fn main() {
let v = vec![42; 10];
do_write("vector.dump", &v);
let v2 = do_read("vector.dump");
assert_eq!(v, v2);
println!("{:?}", v2)
}