SQL-Server Unpivot / Pivot示例

时间:2015-03-13 15:18:05

标签: sql sql-server outsystems

我正在申请管理酒店预订,我需要在一年内显示每月的出勤率。我提出了一个问题,解决了这个问题,但我希望以其他格式呈现。

我当前的查询返回下表(2x12):

January|February|March|April| ..... and so on
   20      15     18     20   ..... and so on

我想要这样的东西(12x2):

January|20
February|15
March|18
... |... 

这是我的疑问:

Select  
        SUM(CASE WHEN datename(month, [CheckIn]) = 'January' or datename(month, [CheckOut]) = 'January' THEN 1 ELSE 0 END) January,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'February' or datename(month, [CheckOut]) = 'February' THEN 1 ELSE 0 END) February,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'March' or datename(month, [CheckOut]) = 'March' THEN 1 ELSE 0 END) March,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'April' or datename(month, [CheckOut]) = 'April' THEN 1 ELSE 0 END)  April,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'May' or datename(month, [CheckOut]) = 'May' THEN 1 ELSE 0 END)  May,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'June' or datename(month, [CheckOut]) = 'June' THEN 1 ELSE 0 END) June,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'July' or datename(month, [CheckOut]) = 'July' THEN 1 ELSE 0 END) July,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'August' or datename(month, [CheckOut]) = 'August' THEN 1 ELSE 0 END) August,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'September' or datename(month, [CheckOut]) = 'September' THEN 1 ELSE 0 END) September,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'October' or datename(month, [CheckOut]) = 'October' THEN 1 ELSE 0 END) October,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'November' or datename(month, [CheckOut]) = 'November' THEN 1 ELSE 0 END) November,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'December' or datename(month, [CheckOut]) = 'December' THEN 1 ELSE 0 END) December
FROM {Booking} INNER JOIN {Status} ON {Booking}.[StatusId] = {Status}.[Id]
WHERE {Booking}.[CheckIn] >= @BeginDate AND {Booking}.[CheckOut]  <= @EndDate AND {Status}.[Label] <> 'Canceled' 

任何帮助都会受到赞赏,我被卡住了,而且网上的信息并不多,谢谢!

2 个答案:

答案 0 :(得分:4)

您似乎正在尝试UNPIVOT

SELECT Month, CheckIns
FROM
  (Select  
        SUM(CASE WHEN datename(month, [CheckIn]) = 'January' or datename(month, [CheckOut]) = 'January' THEN 1 ELSE 0 END) January,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'February' or datename(month, [CheckOut]) = 'February' THEN 1 ELSE 0 END) February,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'March' or datename(month, [CheckOut]) = 'March' THEN 1 ELSE 0 END) March,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'April' or datename(month, [CheckOut]) = 'April' THEN 1 ELSE 0 END)  April,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'May' or datename(month, [CheckOut]) = 'May' THEN 1 ELSE 0 END)  May,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'June' or datename(month, [CheckOut]) = 'June' THEN 1 ELSE 0 END) June,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'July' or datename(month, [CheckOut]) = 'July' THEN 1 ELSE 0 END) July,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'August' or datename(month, [CheckOut]) = 'August' THEN 1 ELSE 0 END) August,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'September' or datename(month, [CheckOut]) = 'September' THEN 1 ELSE 0 END) September,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'October' or datename(month, [CheckOut]) = 'October' THEN 1 ELSE 0 END) October,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'November' or datename(month, [CheckOut]) = 'November' THEN 1 ELSE 0 END) November,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'December' or datename(month, [CheckOut]) = 'December' THEN 1 ELSE 0 END) December
  FROM {Booking} INNER JOIN {Status} ON {Booking}.[StatusId] = {Status}.[Id]
  WHERE {Booking}.[CheckIn] >= @BeginDate AND {Booking}.[CheckOut]  <= @EndDate AND {Status}.[Label] <> 'Canceled'
) monthTotals
UNPIVOT
(CheckIns FOR Month IN
   (January, February, March, April, May, June, July, August, September, October, November, December)
) AS upvt

Here's a simplified SQLFiddle of this

PIVOTUNPIVOT

here's a doc page

答案 1 :(得分:1)

您可以使您的案例陈述更短/更简单,以便更容易阅读。 MONTH()是一个更容易阅读的函数,如果它只是返回一个SUM()就像0那样的

,那么摆脱else就意味着它
SELECT [Month], CheckIns
FROM
  (
  Select  
        SUM(CASE WHEN MONTH([CheckIn]) = 01 or MONTH([CheckOut]) = 01 THEN 1 END) January,
        SUM(CASE WHEN MONTH([CheckIn]) = 02 or MONTH([CheckOut]) = 02 THEN 1 END) February,
        SUM(CASE WHEN MONTH([CheckIn]) = 03 or MONTH([CheckOut]) = 03 THEN 1 END) March,
        SUM(CASE WHEN MONTH([CheckIn]) = 04 or MONTH([CheckOut]) = 04 THEN 1 END) April,
        SUM(CASE WHEN MONTH([CheckIn]) = 05 or MONTH([CheckOut]) = 05 THEN 1 END) May,
        SUM(CASE WHEN MONTH([CheckIn]) = 06 or MONTH([CheckOut]) = 06 THEN 1 END) June,
        SUM(CASE WHEN MONTH([CheckIn]) = 07 or MONTH([CheckOut]) = 07 THEN 1 END) July,
        SUM(CASE WHEN MONTH([CheckIn]) = 08 or MONTH([CheckOut]) = 08 THEN 1 END) August,
        SUM(CASE WHEN MONTH([CheckIn]) = 09 or MONTH([CheckOut]) = 09 THEN 1 END) September,
        SUM(CASE WHEN MONTH([CheckIn]) = 10 or MONTH([CheckOut]) = 10 THEN 1 END) October,
        SUM(CASE WHEN MONTH([CheckIn]) = 11 or MONTH([CheckOut]) = 11 THEN 1 END) November,
        SUM(CASE WHEN MONTH([CheckIn]) = 12 or MONTH([CheckOut]) = 12 THEN 1 END) December
  FROM [Booking] 

  INNER JOIN {Status} ON {Booking}.[StatusId] = {Status}.[Id]
  WHERE {Booking}.[CheckIn] >= @BeginDate AND {Booking}.[CheckOut]  <= @EndDate AND {Status}.[Label] <> 'Canceled'
) MONTHTotals
UNPIVOT
(
CheckIns FOR [Month] IN
   (January, February, March, April, May, June, July, August, September, October, November, December)
) AS upvt