Question

当我尝试从数组中获取时间戳索引时，我得到一个未定义的索引错误。

这是我的页面源

中的多维数组

Array
(
    [0] => Array
        (
            [timestamp] => 14:58:25
        )

    [1] => Array
        (
            [timestamp] => 14:58:43
        )

    [2] => Array
        (
            [timestamp] => 14:58:54
        )

    [3] => Array
        (
            [timestamp] => 15:06:28
        )

)
Array
(
    [0] => Array
        (
            [timestamp] => 08:53:26
        )

    [1] => Array
        (
            [timestamp] => 09:19:42
        )

    [2] => Array
        (
            [timestamp] => 11:41:51
        )

    [3] => Array
        (
            [timestamp] => 11:44:01
        )

    [4] => Array
        (
            [timestamp] => 12:09:23
        )

)

这是我的功能代码：

private function getTimestamps ( $employee_id, $date )
{
    $em = $this->getDoctrine()->getManager();       
    $sql = "SELECT TIME(time_record) as timestamp FROM log WHERE `employee_id` = '{$employee_id}' AND DATE(time_record) = '{$date}'";
    $stmt = $em->getConnection()->prepare($sql);        
    $stmt->execute();        
    $data = $stmt->fetchAll();        
    $output = array ();

    foreach ( $data as $d ) {
        $output[] = $d;
    }

    return $output;
}

public function indexAction()
{



    $em = $this->getDoctrine()->getManager();


    $sql = "SELECT e.id as employee_id,
                   e.firstname as firstname,
                   e.lastname as lastname,
                   DATE(l.time_record) AS requested_date
                   FROM employee e
                   INNER JOIN log l
                   ON l.employee_id = e.id
                   GROUP BY DATE(l.time_record), l.employee_id";


    $stmt = $em->getConnection()->prepare($sql);
    $stmt->execute();
    $logs = $stmt->fetchAll(\PDO::FETCH_ASSOC);

    $timetracking = array ();

    foreach ( $logs as $log ) {

        $timetracking[$log['employee_id']][] = $this->getTimestamps ( $log['employee_id'], $log['requested_date'] );
    }


    foreach ( $timetracking[11] as $time ) {
        echo $time['timestamp'] . " ----- ";
        //print_r($time);
    }
    die ();
}

我在这里做错了什么？请帮忙。

Answer 1

我没有得到你的目标和观点但是尝试：

foreach ( $timetracking[11][0] as $time ) {
        echo $time['timestamp'] . " ----- ";
        //print_r($time);
    }

根据你的评论你需要这个：

foreach ( $timetracking as $next ) {
echo '---NEXT---';
foreach ( $next[0] as $time ) {
        echo $time['timestamp'] . " ----- ";
        //print_r($time);
    }
}

编辑3：

或者如果我终于实现了你的目标：

 foreach ( $logs as $log ) {

        $timetracking[$log['employee_id']] = $this->getTimestamps ( $log['employee_id'], $log['requested_date'] );
    }


    foreach ( $timetracking as $key=>$time ) {
        echo 'empoyee_id : '.$key. '; time '.$time['timestamp'] . " \n";
    }

编辑4 因此，您已发送评论（请勿再次发送，您应修改原始帖子并对问题添加修改）：

<?php foreach ($logs as $log): ?> 
<tr> <td><?php echo $log['firstname'] ?></td>
 <td><?php echo date("d/m/Y") ?></td> 
 <?php foreach ( $timetracking[$log['employee_id']] as $next ): ?> 
 <?php foreach ($next[0] as $time): ?> <td>
 <?php echo $time['timestamp'] ?></td>
  <?php endforeach ?>

此代码与我建议的最后一个代码完全不同!!

所以我再次猜测你的目标是什么，但如果你按照我建议的方式准备你的阵列{strong>编辑3 ，你可以尝试：

logs

PHP数组，循环时未定义索引

1 个答案: