Question

    again:
        while (!s.hasNextInt()) s.next();
        amount = s.nextInt();
    if(amount < 0 || amount > numberOfCards) {
        System.out.println("You need to enter a number between 0 and "+numberOfCards);
        goto again; 
    }

它在C＃中运行良好，但在Java中没有goto。我可以想到大量复杂的重做方法，但我对编写此代码最干净最推荐的方法感兴趣。

Answer 1

愚蠢的方式：

while (true) {
    while (!s.hasNextInt()) s.next();
        amount = s.nextInt();
    if(amount < 0 || amount > numberOfCards) {
        System.out.println("You need to enter a number between 0 and "+numberOfCards);
    } else {
       break;
    }
}

Answer 2

将它包裹在一个循环中：

while (amount < 0 || amount > numberOfCards) {
    while (!s.hasNextInt()) s.next();
    amount = s.nextInt();
    if(amount < 0 || amount > numberOfCards) {
        System.out.println("You need to enter a number between 0 and "+numberOfCards);
    }
}

我该怎么写这段代码？

2 个答案: