Question

我有以下查询：

SELECT  COUNT (*) AS Total, Program, Status
FROM APP_PGM_CHOICE
WHERE Program IN ( 'EX', 'IM')
AND  APP_PGM_REQ_DT  >= '20150101'
AND APP_PGM_REQ_DT  <= '20150131'
AND Status IN ( 'PE','DN','AP')
GROUP BY  Program, Status
ORDER BY  Program, Status

输出是：

Total   Program   Status
12246   "EX"      "AP"
13963   "EX"      "DN"
21317   "EX"      "PE"
540     "IM"      "AP"
2110    "IM"      "DN"
7184    "IM"      "PE"

我希望输出如下：

Total1  Program1   Total2   Program2  Status
12246     EX        540       IM        AP
13963     EX        2110      IM        DN
21317     EX        7184      IM        PE

我可以做ii吗？如果是的话怎么样？

Answer 1

您可以使用UNION查询和一些简单的选择

来执行此操作

SELECT GROUP_CONCAT(total1) as total1, GROUP_CONCAT(proram1) as program1, GROUP_CONCAT(total2) as total2, GROUP_CONCAT(program2) as program2
FROM 
(SELECT total AS total1, program AS program1, null AS total2, null AS program2
WHERE program = 'EX'
UNION
SELECT null AS total1, null AS program1, total AS total2, program AS program2
WHERE program = 'IM') t

这是将行转移到列

的简便方法

Answer 2

是的，你可以这样做：

Select T1.Total Total1, T1.Program Program1, T2.Total Total2, T2.Program Program2, T1.Status

From
(SELECT  COUNT (*) AS Total, Program, Status
FROM APP_PGM_CHOICE
WHERE Program = 'EX'
AND  APP_PGM_REQ_DT  >= '20150101'
AND APP_PGM_REQ_DT  <= '20150131'
AND Status IN ( 'PE','DN','AP')
GROUP BY  Program, Status
ORDER BY  Program, Status) T1

INNER JOIN

(SELECT  COUNT (*) AS Total, Program, Status
FROM APP_PGM_CHOICE
WHERE Program = 'IM'
AND  APP_PGM_REQ_DT  >= '20150101'
AND APP_PGM_REQ_DT  <= '20150131'
AND Status IN ( 'PE','DN','AP')
GROUP BY  Program, Status
ORDER BY  Program, Status) T2 on T1.Status = T2.Status

Answer 3

在sql Temp Table中非常实用且易于使用..

轻松获得输出。

选择总计，程序，状态进入#TempAA 来自CGT Prog ='EX'的地方按状态分组，总计，程序

选择总计，程序，状态进入#TempBB 来自CGT Prog ='IM'的地方按状态分组，总计，程序

选择A.Total为[Total1]，A.Prog为[Program1]，B.Total为[Total2]，B.Prog为[Program2]，A.Status 来自#TempAA A. 内连接#TempBB B on b.Status = A.status

如何将SQL / MySQL查询输出分成多个表？

3 个答案: