Question

我想在MenuTable和SubMenuTable（循环中）中激活查询。

但我的数据是字符串，如下所示：

"102_264,102_273,104_225,103_233,103_229,103_232,101_316,101_244,101_246,101_249"

此处102_264（menuId_subMenuId）

102是menuId
264是subMenuId

所以，我想在上面的表中将此String与fire查询分开。我怎么能这样做？

Answer 1

您可以使用爆炸功能或使用列表，最后使用 json_encode 功能将其转换为JSON格式。这段代码可以帮你试试，

$str="102_264,102_273,104_225,103_233,103_229,103_232,101_316,101_244,101_246,101_249";

 $arrayComma = explode(',', $str);

 $menu = array();
 $subMenu = array();

 foreach($arrayComma AS $val){
      list($menu[], $subMenu[]) = explode('_', $val);
 }

 $json = array();

 $json=array("menu" => $menu, "submenu" => $subMenu);

 echo json_encode($json);

快乐的编码..！

Answer 2

您正在寻找爆炸功能。

$array = explode($string,','); //Will contain array $array[0] = "102_264" etc

foreach($array as $arr){
   $explodedArr = explode($arr, '_');
   $menuId = $explodedArr[0]; //Contains 102
   $subMenuId = $explodedArr[1]; //Contains 264
}

Answer 3

$str='102_264,102_273,104_225,103_233,103_229,103_232,101_316,101_244,101_246,101_249';
$arr=array();
$arr=explode(',', $str);

for ($i=0; $i<sizeof($arr) ; $i++) 
{ 
    $arr2=array();
    $arr2=explode('_',$arr[$i]);
    $sql="select * from abc where menu_id=".$arr2[0]." and sub_menu_id=".$arr2[1]."";
    echo $sql."    ";
}

Answer 4

基本上你想爆炸字符串。快速的3D阵列方式：

$data = "102_264,102_273,104_225,103_233,103_229,103_232,101_316,101_244,101_246,101_249";

$result = [];
// retrieve array by splittting string with every comma
foreach(explode(',', $data) as $value) {

    // retrieve Ids by splitting string with underscore
    $serie = explode('_', $value);
    $result[] = array(
        'menuId' => $serie[0],
        'subMenuId' => $serie[1],
    );
}

您将拥有单独的子阵列中的所有内容，以便轻松循环查询。

Answer 5

试试这个，它结合了explode和map，可以在一行代码中为您提供数据。

$results = array_map(function($data){
    return explode("_",$data);
}, explode(",", $tmp));

foreach($results as $result){
    echo "menuId: " . $result[0]." subMenuId: ".$result[1]."<br />";
}

给你

menuId: 102 subMenuId: 264
menuId: 102 subMenuId: 273
menuId: 104 subMenuId: 225
menuId: 103 subMenuId: 233
menuId: 103 subMenuId: 229
menuId: 103 subMenuId: 232
menuId: 101 subMenuId: 316
menuId: 101 subMenuId: 244
menuId: 101 subMenuId: 246
menuId: 101 subMenuId: 249

如何在PHP中为String创建两个数组以用于json输出

5 个答案: