将值分配给数组时键入不匹配错误

时间:2015-03-13 06:59:17

标签: vba excel-vba excel

如果数据为红色,则将其存储在数组中并将其显示在MSGBOX中。但不能因为我收到类型不匹配错误。

             Name         Age        Sex

             John         18          m
             Rita         15          f -------> RED   
             Phil         15          m -------> Red
             Letty        15          f --------> Red
             and so on  

Sub msg()
Dim dar() As Variant
Dim j3 As Variant
r3 = Range("a1").SpecialCells(xlCellTypeLastCell).Row
For i3 = 1 To r3
    If (Range("E" & i3).Interior.Color = RGB(255, 0, 0)) = True Then
        j3 = j3 + 1

        ' Getting Error at this line Type Mismatch error
        Set dar(i3) = Range("b" & i3, "f" & i3).Value

        MsgBox x
    End If
Next i3   
End Sub

2 个答案:

答案 0 :(得分:3)

丢失设置关键字。
Set x(i3) = Range("b" & i3, "f" & i3).Value更改为
x(i3) = Range("b" & i3, "f" & i3).Value
设置关键字用于分配对象,您尝试分配值。这就是错误的原因。

编辑1

我们忘了初始化数组。

Sub msg()
Dim dar() As Variant
Dim j3 As Variant
r3 = Range("a1").SpecialCells(xlCellTypeLastCell).Row
For i3 = 1 To r3
    If (Range("E" & i3).Interior.Color = RGB(255, 0, 0)) = True Then
        ReDim Preserve dar(j3)
        dar(j3) = Range("b" & i3).Value    'beware, that I have changed the dar(i3) to dar(j3)
        j3 = j3 + 1
        MsgBox x
    End If
Next i3

End Sub

编辑2

Sub msg()
Dim dar() As Variant
Dim j3 As Variant

r3 = Range("a1").SpecialCells(xlCellTypeLastCell).Row
For i3 = 2 To r3 'changed to start at row 2, in row 1 there are headers I guess
    If (Range("E" & i3).Interior.Color = RGB(255, 0, 0)) = True Then

        ReDim Preserve dar(j3)
        dar(j3) = Range(Cells(i3, 1), Cells(i3, 6))

        'store the values from this row only into string
        For y = 1 To 6
            If y = 1 Then
                strMessage = dar(j3)(1, y)
            Else
                strMessage = strMessage & " || " & dar(j3)(1, y)
            End If
        Next y

        j3 = j3 + 1

        'store all previous strings one string, with multiple rows
        If j3 = 1 Then
            strMessage2 = strMessage
        Else
            strMessage2 = strMessage2 & Chr(10) & strMessage 'chr(10) is a line break
        End If

    End If
Next i3

If Not IsEmpty(strMessage2) Then
    MsgBox strMessage2, Title:="Red data"
End If

End Sub

答案 1 :(得分:1)

请检查此行

Range("b" & i3, "f" & i3).Value。它什么都没有取得任何价值。 如果您测试此行立即窗口则显示错误。请修理 如果你想存储两个值意味着2d-数组,则声明2D数组。

相关问题