我编写了一个程序，它从文本文件中读取帐户值，然后将这些值分配给每个帐户的变量。完成此操作后，从同一文本文件中读取，对每个帐户值执行的操作将以“Account＃Actiontype ActionModifier”格式标识。当我插入printfs进行检查时，正在扫描所有正确的值并存储正确的值，但是在打印正确的值之后，值立即通过else if循环。当由于某种原因执行此操作时，无论如何将值读取为1并且正在执行else if循环中的操作，就好像它等于1一样。
loopState = 1;
while(loopState != 0)
{
for(i = 1;i < 100 ;i++)
{
if(i < 6)// This executes fine
{
fscanf(bankfile,"%f",&accValue);
switch(i)
{
case 1:
acc1 = accValue;
break;
case 2:
acc2 = accValue;
break;
case 3:
acc3 = accValue;
break;
case 4:
acc4 = accValue;
break;
case 5:
acc5 = accValue;
printf("Done module one\n");
break;
}
}
else // scan for the the first value, than the second, then the third
{
fscanf(bankfile,"%d",&accNum);
if(accNum != 0)
{
fscanf(bankfile,"%c",&accAction);
if(accAction == 'W' || accAction == 'D')
{
fscanf(bankfile,"%f",&actValue);
printf("%d %c %.2f\n",accNum,accAction,actValue);//this will be correct
printf("%d\n",accNum); //this will print say "2"
if(accNum = 1)//but this if statement will be run
{//thus printing the below printf
printf("If accNum = 1 this will print\n");
switch(accAction)
{
case 'W':
final1 = withdrawl(acc1,actValue);
break;
case 'D':
final1 = deposit(acc1,actValue);
break;
}
}
else if(accNum = 2)
{
switch(accAction)
{
case 'W':
final2 = withdrawl(acc2,actValue);
break;
case 'D':
final2 = deposit(acc2,actValue);
break;
}
}
else if(accNum = 3)
{
switch(accAction)
{
case 'W':
final3 = withdrawl(acc3,actValue);
break;
case 'D':
final3 = deposit(acc3,actValue);
break;
}
}
else if(accNum = 4)
{
switch(accAction)
{
case 'W':
final4 = withdrawl(acc4,actValue);
break;
case 'D':
final4 = deposit(acc4,actValue);
break;
}
}
else if(accNum = 5)
{
switch(accAction)
{
case 'W':
final5 = withdrawl(acc5,actValue);
break;
case 'D':
final5 = deposit(acc5,actValue);
break;
}
}
}
else if(accAction == 'B' || accAction == 'U')
{
printf("%d %c\n",accNum,accAction);//this will be correct
printf("%d\n",accNum);//this will print say "4"
if(accNum = 1)//but this if statement will be run
{//thus printing this printf below
printf("If accNum = 1 this will print\n");
switch(accAction)
{
case 'B':
final1 = balance(acc1);
break;
case 'U':
final1 = update(acc1);
break;
}
}
else if(accNum = 2)
{
switch(accAction)
{
case 'B':
final2 = balance(acc2);
break;
case 'U':
final2 = update(acc2);
break;
}
}
else if(accNum = 3)
{
switch(accAction)
{
case 'B':
final3 = balance(acc3);
break;
case 'U':
final3 = update(acc3);
break;
}
}
else if(accNum = 4)
{
switch(accAction)
{
case 'B':
final4 = balance(acc4);
break;
case 'U':
final4 = update(acc4);
break;
}
}
else if(accNum = 5)
{
switch(accAction)
{
case 'B':
final5 = withdrawl(acc5,actValue);
break;
case 'U':
final5 = deposit(acc5,actValue);
break;
}
}
}
}
else
loopState = 0;
}
}
}
printf("Exited Loop");
}
根据我的理解，如果仅将其视为正确值之前的行，我无法看到值被改变的位置
答案 0 :(得分：2)
您的条件陈述正在进行分配。
else if (accNum = 3)
应该是
else if (accNum == 3)