Question

如何将2个数组字符串组成1个数组字符串，在那里我可以打印出所有52个扑克牌？

我的代码：

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<string.h>


int main() {
    char deck[52];
    char suits[] = {"Hearts","Diamonds","Clubs","Spades"};
    char values[]= {"Ace","Two","Three","Four","Five","Six",\
                    "Seven","Eight","Nine","Ten","Jack",\
                    "Queen","King"};
    int V, S, d = 0;
    char string;
    for ( S= 0; S <4; S++) {
        for (V =0; V< 13; V++) {
            string = strcat( values[V], suits[S]);
            deck[d] = string;
            printf("%s\n", string);//prints out all the 52 playing cards
            d++;
        }
    }

    return 0;
}

当我执行程序时，出现问题，要求我调试程序或关闭程序，最后我关闭了程序，没有返回任何内容。你能给我一个有效的答案吗？

Answer 1

检查以下代码，修复代码中的问题：你的代码的问题是你试图在打印之前修改实际的字符串，因此在下一次迭代中有一个修改过的字符串。所以只需将值和套装复制到数组并打印出来，如下所示。

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<string.h>


int main()
{
  int i=0;
  char deck[30] = "";
  char suits[][30] = {"Hearts","Diamonds","Clubs","Spades"};
  char values[][30]= {"Ace","Two","Three","Four","Five","Six",
                    "Seven","Eight","Nine","Ten","Jack",
                    "Queen","King"};
  int V, S;
  for ( S= 0; S <13; S++)
  {
    for (V =0; V< 4; V++){
    memset(deck,0,sizeof(deck));/* Clear the buffer before writing new value*/
    strcpy( deck, values[S]);
    strcat(deck,suits[V]);
    printf("%s\n", deck);//prints out all the 52 playing cards
    i++;
   }
  }
    printf("Number of playing cards: %d\n",i);

    return 0;
  }

Answer 2

strcat()会返回char *，指向char的指针，而不是char。

您甚至不需要考虑strcat()的返回值，因为目标指针（第一个参数）现在将包含连接字符串，假设已经分配了足够的内存。

所以在你的代码中，你试图将连接的字符串放到values[V]，当已经分配给它的内存不足时，这可能会失败。

最好的方法是分配一些内存（就像你对deck[]所做的那样）并将其全部设置为零。然后保持strcat()。

strcat(deck, values[V]);
strcat(deck, suits[S]);

Answer 3

使用strcpy和strcat的替代方法是使用sprintf。

#include<stdio.h>
#include<string.h>

#define NUM_SUITS 4
#define CARDS_PER_SUIT  13
#define TOTAL_CARDS (NUM_SUITS * CARDS_PER_SUIT)

int main() 
{
    char deck[TOTAL_CARDS][24];
    char* suits[NUM_SUITS] = {"Hearts","Diamonds","Clubs","Spades"};
    char* values[CARDS_PER_SUIT]= {"Ace","Two","Three","Four","Five","Six",
                    "Seven","Eight","Nine","Ten","Jack",
                    "Queen","King"};

    int s, c, i;

    for(s = 0; s < NUM_SUITS; s++)
    {
       for(c = 0; c < CARDS_PER_SUIT; c++)
       {
           sprintf(deck[(s * CARDS_PER_SUIT) + c], "%s of %s", values[c], suits[s]);
       }
    }

    for(i = 0; i < TOTAL_CARDS; i++)
    {
        printf("%s\n", deck[i]);
    }

    return 0;
}

如何在C中将两个数组字符串组成一个数组字符串

3 个答案: