我有连接继承的实体:
力撑
@Entity
@Inheritance(strategy=InheritanceType.JOINED)
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "supporterType")
@JsonSubTypes({
@JsonSubTypes.Type(value = PersonSupporterEntity.class, name = "PERSON"),
@JsonSubTypes.Type(value = CompanySupporterEntity.class, name = "COMPANY")
})
@DiscriminatorColumn(name="supporter_type")
@Table(name = "supporter")
public class SupporterEntity extends UpdatableEntity {
private long id;
private SupporterType supporterType;
private PartnerEntity partner;
...
}
PersonSupporter
@Entity
@DiscriminatorValue("PERSON")
@Table(name = "person_supporter")
public class PersonSupporterEntity extends SupporterEntity {
...
}
CompanySupporter
@Entity
@DiscriminatorValue("COMPANY")
@Table(name = "company_supporter")
public class CompanySupporterEntity extends SupporterEntity {
...
}
我有另一个引用SupporterEntity的实体
@Entity
@Table(name = "contact")
public class ContactEntity extends UpdatableEntity {
private long id;
private SupporterEntity supporter;
...
@ManyToOne // same error with @OneToOne
@JoinColumn(name = "supporter_id", referencedColumnName = "id", nullable = false)
public SupporterEntity getSupporter() {
return supporter;
}
...
}
存储库
@Transactional
@RepositoryRestResource(collectionResourceRel = "supporters", path = "supporters")
public interface SupporterEntityRepository extends JpaRepository<SupporterEntity, Long> {
@Transactional(readOnly = true)
@RestResource(path = "by-partner", rel = "by-partner")
public Page<SupporterEntity> findByPartnerName(@Param("name") String name, Pageable pageable);
}
@Transactional
@RepositoryRestResource(collectionResourceRel = "person_supporters", path = "person_supporters")
public interface PersonSupporterEntityRepository extends JpaRepository<PersonSupporterEntity, Long> {
}
@Transactional
@RepositoryRestResource(collectionResourceRel = "company_supporters", path = "company_supporters")
public interface CompanySupporterEntityRepository extends JpaRepository<CompanySupporterEntity, Long> {
}
@Transactional
@RepositoryRestResource(collectionResourceRel = "contacts", path = "contacts")
public interface ContactEntityRepository extends JpaRepository<ContactEntity, Long> {
@Transactional(readOnly = true)
@RestResource(path = "by-supporter", rel = "by-supporter")
public ContactEntity findBySupporterId(@Param("id") Long id);
}
我使用Spring Boot,Spring Data REST,Spring Data JPA,Hibernate,Jackson。当我尝试使用这样的帖子请求创建一个新的ContactEntity时:
{
"supporter":"/supporters/52",
"postcode":"1111",
"city":"Test City 1",
"address":"Test Address 1",
"email":"test1@email.com",
"newsletter":true
}
我得到了这个例外:
Caused by: com.fasterxml.jackson.databind.JsonMappingException: Unexpected token (VALUE_STRING), expected FIELD_NAME: missing property 'supporterType' that is to contain type id (for class com.facer.domain.supporter.SupporterEntity)
at [Source: HttpInputOverHTTP@4321c221; line: 1, column: 2] (through reference chain: com.facer.domain.supporter.ContactEntity["supporter"])
at com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:148) ~[jackson-databind-2.4.4.jar:2.4.4]
经过2天的调试我发现了一种方法,但我猜对了。所以,如果我这样张贴:
{
"supporter":{
"supporterType":"PERSON",
"id":"52"
},
"postcode":"1111",
"city":"Test City 1",
"address":"Test Address 1",
"email":"test1@email.com",
"newsletter":true
}
它有效,但我不知道为什么。其他请求有什么问题?当引用的实体没有继承时,它就像其他地方一样。
答案 0 :(得分:3)
使用RelProvider
:
@JsonTypeInfo
为RelProvider
子类
SupporterEntity
@Component
@Order(Ordered.HIGHEST_PRECEDENCE)
public class SupporterEntityRelProvider implements RelProvider {
@Override
public String getCollectionResourceRelFor(final Class<?> type) {
return "supporters";
}
@Override
public String getItemResourceRelFor(final Class<?> type) {
return "supporter";
}
@Override
public boolean supports(final Class<?> delimiter) {
return org.apache.commons.lang3.ClassUtils.isAssignable(delimiter, SupporterEntity.class);
}
}
另见:
答案 1 :(得分:1)
看起来像杰克逊的问题。具体而言,它是com.fasterxml.jackson.databind.deser.SettableBeanProperty
中的以下代码:
if (_valueTypeDeserializer != null) {
return _valueDeserializer.deserializeWithType(jp, ctxt, _valueTypeDeserializer);
}
return _valueDeserializer.deserialize(jp, ctxt);
如果没有继承,则会调用_valueDeserializer.deserialize
,而后者会运行一些Spring代码将URI转换为Supporter
。
当继承_valueDeserializer.deserializeWithType
被调用时,vanilla Jackson当然需要一个对象,而不是URI。
如果supporter
可以为空,您可以先POST
到/contacts
,然后PUT
支持者的/contacts/xx/supporter
URI。不幸的是,我不知道任何其他解决方案。
答案 2 :(得分:0)
您应该能够通过在属性/方法级别设置@JsonTypeInfo(use = JsonTypeInfo.Id.NONE)来解决此问题,例如
试试这个:
@ManyToOne // same error with @OneToOne
@JoinColumn(name = "supporter_id", referencedColumnName = "id", nullable = false)
@JsonTypeInfo(use= JsonTypeInfo.Id.NONE)
public SupporterEntity getSupporter() {
return supporter;
}