尝试将数组的值粘贴到变量中

时间:2015-03-12 15:45:30

标签: php sql arrays oop

目前,我一直坚持如何将数组的值添加到变量中,以便在查询中输出。

以下是我的数据:

try {

    $link->create(array(

        'uid'       =>  $user->data()->id,
        'name'      =>  Input::get('name'),
        'hyperlink' =>  Input::get('hyperlink')

    ));

} catch (Exception $e) {

    die($e->getMessage());

}

使用此功能,我试图将该数组中的值转换为1个变量:

    public function insert($table, $fields = array()) {

        if (count($fields)) {

            $keys = array_keys($fields);

            $x = 1;

            foreach ($fields as $field => $values) {

                if ($x < count($fields)) {

                    $values .= ', ';

                }

                $x++;

            }

            $sql = "INSERT INTO `$table` (`" . implode('`, `', $keys) . "`) VALUES ({$values})";

            die($sql);

            if (!$this->query($sql, $fields)->error()) {

                return true;

            }

        }

        return false;

    }

但是当我回显sql时,它只给出了数组的最后一个值。我究竟做错了什么?

谢谢!

4 个答案:

答案 0 :(得分:1)

你可以尝试这样的事情,减少循环,实际上可以组合成一行......编辑:忽略引用值...适当更新

if (count($fields)) {

  $field_list = implode(", ", array_keys($fields));
  $value_list = implode("', '", array_values($fields));

  $sql =  "insert into `$table` ($field_list) values('$value_list')";

}

答案 1 :(得分:1)

这是另一个选项,我无法弄清楚你的脚本出了什么问题,它看起来是正确的但是无法找到问题。我总是在动态插入db值时使用此类方法。

   function insertRecord ($fieldarray)
   {
      $this->errors = array();


      //Connect to the DB for table insert
      global $dbconnect, $query;
      $dbconnect = db_connect($this->dbname) or trigger_error("SQL", E_USER_ERROR);

     //Now, using the contents of $fieldlist which was set in the class constructor we can edit the input array to filter out any items which do not belong in this database table. This removes the SUBMIT button, for example.

      $fieldlist = $this->fieldlist;
      foreach ($fieldarray as $field => $fieldvalue) {
         if (!in_array($field, $fieldlist)) {
            unset ($fieldarray[$field]);
         } // if
      } // foreach

      //Now construct the query string to insert a new 
      //record into the database:

      $query = "INSERT INTO $this->tablename SET ";
      foreach ($fieldarray as $item => $value) {
         $query .= "$item='$value', ";
      } // foreach

      //You may have noticed that each 'name=value' pair was appended 
      //to the query string with a trailing comma as a separator, 
      //so we   must remove the final comma like so:

      $query = rtrim($query, ', ');

      //Now execute the query. Notice here that instead of the default 
      //error checking I look specifically for a 'duplicate key' error  
      //and return a simple error message rather terminating the whole   
      //script with a fatal error.

      $result = @mysql_query($query, $dbconnect);
      if (mysql_errno() <> 0) {
         if (mysql_errno() == 1062) {
            $this->errors[] = "A record already exists with this ID.";
         } else {
            trigger_error("SQL", E_USER_ERROR);
         } // if
      } // if

      //Last act is to return control to the calling script.

      return;

   } // insertRecord

恕我直言,上面的函数对插入语句和错误处理进行了必要的检查,我发现它很有用。

答案 2 :(得分:0)

我认为您可以使用函数array_values,就像使用函数array_keys更容易实现这一点。

public function insert($table, $fields = array()) {

        if (count($fields)) {

            $keys = array_keys($fields);
            $values = array_values($fields); // why another logic for the same result.. ?

            $sql = "INSERT INTO `$table` (`" . implode('`, `', $keys) . "`) VALUES (`" . implode('`, `', $values) . "`)";

            die($sql);

            if (!$this->query($sql, $fields)->error()) {

                return true;

            }

        }

        return false;

    }

答案 3 :(得分:0)

问题是$values = $values在foreach循环中。

foreach ($fields as $field => $values) {
    // The problem is right here, each time this loops, you are
    // setting the entire $values variable to be just the current iteration
    // of the $fields variable.

    $values = $values;

    if ($x < count($fields)) {

        $values .= ', ';

    }

    $x++;

}

请改为尝试:

$sql_values = '';
foreach ($fields as $field => $values) {

    if ($x < count($fields)) {

        $sql_values.= $values.', ';

    }

    $x++;

}

$sql = "INSERT INTO `$table` (`" . implode('`, `', $keys) . "`) VALUES ($sql_values)";