Question

我有以下XML：

<LOCALCELL_V18 ID = "0x2d100000">
  <MXPWR ID = "0x3d1003a0">100</MXPWR> 
</LOCALCELL_V18>
<LOCALCELL_V18 ID = "0x2d140000">
  <MXPWR ID = "0x3d1403a0">200</MXPWR>  
</LOCALCELL_V18>
<LOCALCELL_V18 ID = "0x2d180000">  
  <MXPWR ID = "0x3d1803a0">300</MXPWR>   
</LOCALCELL_V18>

我想获得每个<MXPWR>的内部文字。但是，不允许使用ID＃来定位内部文本，因为它并不总是相同的。这是我的代码：

XmlNodeList LocalCell = xmlDocument.GetElementsByTagName("LOCALCELL_V18");

foreach (XmlNode LocalCell_Children in LocalCell)
{
    XmlElement MXPWR = (XmlElement)LocalCell_Children;
    XmlNodeList MXPWR_List = MXPWR.GetElementsByTagName("MXPWR");
    for (int i = 0; i < MXPWR_List.Count; i++)
    {
       MaxPwr_form_str = MXPWR_List[i].InnerText;
    }
}

任何意见将不胜感激。

Answer 1

我会使用xpath。它专为此类问题而设计。类似的东西：

using System.Xml;
using System.Xml.XPath;
....
string fileName = "data.xml"; // your file here
XPathDocument doc = new XPathDocument(fileName);
XPathNavigator nav = doc.CreateNavigator();

// Compile an xpath expression
XPathExpression expr = nav.Compile("./LOCALCELL_V18/MXPWR");
XPathNodeIterator iterator = nav.Select(expr);

// Iterate on the node set
while (iterator.MoveNext())
{
    string s = iterator.Current.Value;
}

当我在你的XML文件上运行它（包装在根节点中）时，我得到：

s = 100
s = 200
s = 300

Answer 2

我会使用XLinq：

using System.Xml.Linq;

var xDoc = XDocument.Load("data.xml");

var mxpwrs = xDoc.Descendants("MXPWR");
foreach (var mxpwr in mxpwrs)
{
    Console.WriteLine(mxpwr.Value);
}

如何搜索和导航XML节点

2 个答案: