Question

我想要一些通用方法将对象转换为xml节点：

如果我有这样的xml nodes：

<BusinessObject xmlns="http://xmlns.oracle.com/bpm/bpmobject/Data/BusinessObject">&lt;?xml version="1.0" encoding="utf-16"?>
&lt;BusinessObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  &lt;attribute1>sss&lt;/attribute1>
  &lt;attribute2>sss&lt;/attribute2>
&lt;/BusinessObject></BusinessObject>

我将其转换为Json，就像那样

 {
    "-xmlns": "http://xmlns.oracle.com/bpm/bpmobject/Data/BusinessObject",
    "#text": "<?xml version=\"1.0\" encoding=\"utf-16\"?>
<BusinessObject xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">
  <attribute1>sss</attribute1>
  <attribute2>sss</attribute2>
</BusinessObject>"
}

然后到c＃class：

public class Rootobject
    {
        public string xmlns { get; set; }
        public string text { get; set; }
    }

现在如何在设置其值后再将其反转为xml节点？我想要一个不是这个例子的通用解决方案

Answer 1

你正在寻找

XML serialization

     public class Rootobject
     {
        public string xmlns { get; set; }
        public string text { get; set; }
     }



    public static void Main(string[] args) 
    { 
      Rootobject details = new Rootobject();
      details.xmlns = "myNamespace";
      details.text = "Value";

      Serialize(details);
   }   

   static public void Serialize(Rootobject details)
   { 
     XmlSerializer serializer = new XmlSerializer(typeof(Rootobject)); 
     using (TextWriter writer = new StreamWriter(@"C:\Xml.xml"))
     {
       serializer.Serialize(writer, details); 
     } 
   }

Answer 2

您可以使用XML Serialization将Class转换为XML，反之亦然。

供参考，请阅读C# Tutorial - XML Serialization。

您还可以参考XML Schema Definition Tool

Answer 3

示例：

[DataContract] public class MyClass1 { [DataMember] public string name; [DataMember] public int age; }

序列化/反序列化

MyClass1 obj = new MyClass1(); DataContractSerializer dcs = new DataContractSerializer(typeof(MyClass1)); using (Stream stream = new FileStream(@"C:\tmp\file.xml", FileMode.Create, FileAccess.Write)) { using (XmlDictionaryWriter writer = XmlDictionaryWriter.CreateTextWriter(stream, Encoding.UTF8)) { writer.WriteStartDocument(); dcs.WriteObject(writer, obj); } }

Answer 4

我认为您需要将Serializable属性应用于您的类才能序列化它。这可以确保您的类不使用某些无序列化属性。

[Serializable]
public class Rootobject
{
    public string xmlns { get; set; }
    public string text { get; set; }
}

如何将类转换为xml节点？

4 个答案: