Question

好的，我有两个MySQL表;一个称为users，另一个称为likes。

用户表

id         name
-----      ------
1          Mark
2          John
3          Paul
4          Dave
5          Chris

喜欢表格

liked_by    liked  match_id
-----      ------    --------
  1          2         1
  2          1         2
  1          3         3
  2          3         4
  1          5         5
  5          1         6

我能够成功加入两个表，如下所示

SELECT users.id, likes.*
FROM users
JOIN likes
ON users.id = likes.liked

但是，我不确定如何格式化WHERE子句以便返回以下行。

name      liked_by    liked     match_id
------    -------     --------  -------- 
Mark         1           3         3
John         2           3         4

正如您所看到的，我正在尝试返回Mark和John都喜欢同一个用户的行。在这种情况下，它是用户3，或保罗。我尝试将以下子句添加到查询中，但它显然不起作用。

WHERE (likes.liked_by = '1' OR likes.liked_by = '2')

Answer 1

找到有多行的喜欢（喜欢？）？否则它只是一个内部联接：

select *
from Likes as l inner join Users as u on u.id = l.liked_by
where liked in (
    select liked
    from Likes
    --where liked_by in (:userid1, :userid2) /* optional: specific pair of users */
    --where liked (:userid1, :userid2) /* optional: specific likee */
    group by liked
    having count(*) > 1
)

我听到很多in子查询不能很好地优化MySQL。由于分组将保证一对一的关系，因此很容易将其转换为派生表/内联视图/嵌套视图中的内部联接或者您称之为的任何内容。

Answer 2

您需要自己加入likes表格，以获取喜欢特定用户的用户对列表。查询非常简单。

测试数据：

CREATE TABLE users (id INT, name VARCHAR(100));
INSERT INTO users(id, name) VALUES (1,'Mark'), (2,'John'), (3,'Paul'), (4,'Dave'), (5,'Chris');

-- Note: I assumed that match_id is a primary key
CREATE TABLE likes (match_id INT PRIMARY KEY AUTO_INCREMENT, liked_by INT, liked INT);
INSERT INTO likes(liked_by, liked) VALUES (1,2), (2,1), (1,3), (2,3), (1,5), (5,1);

实际查询：

SELECT CONCAT(user1.name, ' and ', user2.name, ' like ', user3.name) AS `Readable result`
-- join the likes table with itself where two users like the same user
FROM likes AS like1
INNER JOIN likes AS like2 ON like1.liked = like2.liked AND
                             like1.match_id < like2.match_id
-- join the result with user table three times to obtain names of all users involved
INNER JOIN users AS user1 ON like1.liked_by = user1.id
INNER JOIN users AS user2 ON like2.liked_by = user2.id
INNER JOIN users AS user3 ON like1.liked = user3.id

结果：

+--------------------------+
| Readable result          |
+--------------------------+
| Mark and John like Paul  |
| John and Chris like Mark |
+--------------------------+

基于相互喜欢在MySQL中加入两个表

2 个答案: