Question

我有两个名为Edge and Graph的类，我需要通过循环和从Graph Object中检索，将一组边缘对象（在那些类外面）发送给Graph对象。

图表类

class Graph
{

/**
 * Array of edge objects
 *
 * @var array
 */
protected $edges;

/**
 * Set edges of the graph
 *
 * @param Edge edge object
 */
public function __construct(Edge $edge)
{
    $this->setEdges($edge);
}

/**
 * Get edges
 *
 * @return array array of edge objects
 */
public function getEdges()
{
    return $this->edges;
}

/**
 * Set Edges
 *
 * @param Edge Edge object
 */
public function setEdges(Edge $edge)
{

$this->edges[] = $edge;

}

}

通过边缘循环，

$edges = array(
        array("point1" => "a", "point2" => "b", "value" => 7),
        array("point1" => "a", "point2" => "c", "value" => 9),
        array("point1" => "a", "point2" => "f", "value" => 14.00)
)

$graph = null;
foreach ($edges as $edge) {
    $edgeObj = new Edge($edge['point1'], $edge['point2'], $edge['value']);
    $graph = new Graph($edgeObj);

}

但是$ graph只返回最后一个Edge对象，我知道这是因为我覆盖了$ graph。我做错了什么？

Answer 1

你完全自己回答了。您在循环的每次迭代时都会覆盖$graph，并使用Graph对象的全新实例。

首先，删除构造函数以允许您创建Graph的实例而无需首先需要Edge实例（即在循环外部），然后使用已编写的setEdges()方法将每个新创建的Edge实例添加到类中的数组中。

然后，将您的代码更改为：

$edges = array(
        array("point1" => "a", "point2" => "b", "value" => 7),
        array("point1" => "a", "point2" => "c", "value" => 9),
        array("point1" => "a", "point2" => "f", "value" => 14.00)
)

$graph = new Graph();
    foreach ($edges as $edge) {
        $edgeObj = new Edge($edge['point1'], $edge['point2'], $edge['value']);
        $graph->setEdges($edgeObj);

    }

将对象存储在数组中并使用PHP进行检索

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