Question

请注意，此问题对于我的HTTP通话是唯一的。

我环顾四周，有些人说httpResponse.getEntity().consumeContent();

但我可以使用它，因为我需要提供返回数据。

我将我的API doInBackground ....称为return api.post("analytics", params);

如何将无效的SingleClientConnManager修复到此http帖子中：

public String post(String url, List<NameValuePair> params) {
    HttpPost request = new HttpPost(BASEURL + url); 
    HttpResponse response;

    try {
        request.setEntity(new UrlEncodedFormEntity(params, "UTF-8"));
        response = client.execute(request);
        HttpEntity entity = response.getEntity();            

        return EntityUtils.toString(entity);
    } 
    catch(ClientProtocolException e) {            
        return e.toString();
    } 
    catch(IOException e) {           
        return e.toString();
    }       
}//end post

这是我得到的错误：

03-12 12:33:46.926: V/Activity(28803): YourAsyncTask.class
03-12 12:33:46.926: W/Activity(28803): -------------------------------------------------
03-12 12:33:46.926: W/SingleClientConnManager(28803): Invalid use of SingleClientConnManager: connection still allocated.
03-12 12:33:46.926: W/SingleClientConnManager(28803): Make sure to release the connection before allocating another one.
03-12 12:33:46.926: I/System.out(28803): AsyncTask #4 calls detatch()
03-12 12:33:46.926: D/Toast(28803):  checkMirrorLinkEnabled returns : false
03-12 12:33:46.926: D/Toast(28803): showing allowed
03-12 12:33:46.926: W/AsyncTaskExecutor(28803): java.util.concurrent.ThreadPoolExecutor$Worker@433abe80[State = -1, empty queue] | AsyncTask # 5

Answer 1

搜索后，I found this solution

HttpResponse httpResponse = httpClient.execute(httpPost);

//instead of httpClient use getThreadSafeClient() method.
HttpResponse httpResponse = getThreadSafeClient().execute(httpPost);

public static DefaultHttpClient getThreadSafeClient() {
        DefaultHttpClient client = new DefaultHttpClient();
        ClientConnectionManager mgr = client.getConnectionManager();
        HttpParams params = client.getParams();
    client = new DefaultHttpClient(new ThreadSafeClientConnManager(params,
                mgr.getSchemeRegistry()), params);
   
        return client;
    }

Android无效使用SingleClientConnManager：仍然分配连接

1 个答案: