我正在使用带有此代码的KenBurnsView库:
mHeaderPicture.setResourceIds(R.drawable.picture0, R.drawable.picture1);
正如您所看到的,它需要可绘制的资源ID。
我想要做的是将所有照片的URL转换为可绘制的资源ID。 照片网址是这样的:
http://example.com/image.jpg
http://example.com/image2.jpg
http://example.com/image3.jpg
http://example.com/image4.jpg
我在这里尝试了这段代码并且无效:
Bitmap drawable_from_url(String url) throws java.net.MalformedURLException, java.io.IOException {
Bitmap x;
HttpURLConnection connection = (HttpURLConnection)new URL(url) .openConnection();
connection.setRequestProperty("User-agent","Mozilla/4.0");
connection.connect();
InputStream input = connection.getInputStream();
x = BitmapFactory.decodeStream(input);
return x;
}
我已经在网上阅读了很多问题和答案,但我找不到一个好的教程或解决方案。
答案 0 :(得分:3)
尝试将此库放入您的项目中。它是一个有用的库。 http://square.github.io/picasso/
样本用法:
Picasso.with(context).load("http://example.com/image.jpg").into(imageView);
如何从imageView获取drawable:
Drawable myDrawable = imageView.getDrawable();
答案 1 :(得分:0)
您无法将位图转换为资源ID。资源ID仅适用于APK中的资源。您必须编辑或扩展KenBurnsView类以接受Bitmap对象,例如通过添加如下函数:
public void setBitmaps(Bitmap... bitmaps) {
for (int i = 0; i < mImageViews.length; i++) {
mImageViews[i].setImageBitmap(bitmaps[i]);
}
}
然后您可以使用drawable_from_url()
传递加载的位图答案 2 :(得分:0)
您忘了将setDoInput添加到连接
public Bitmap getBitmapFromURL(String src) {
try {
URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
return myBitmap;
} catch (IOException e) {
e.printStackTrace();
return null;
}
}
答案 3 :(得分:-1)
添加异步任务...
new DownloadImageTask((ImageView) findViewById(R.id.imageView1))
.execute(url);
}
public void onClick(View v) {
startActivity(new Intent(this, IndexActivity.class));
finish();
}
private class DownloadImageTask extends AsyncTask<String, Void, Bitmap> {
ImageView mHeaderPicture;
public DownloadImageTask(ImageView mHeaderPicture){
this.mHeaderPicture= mHeaderPicture;
} protected Bitmap doInBackground(String... urls) {
String urldisplay = urls[0];
Bitmap mIcon11 = null;
try {
InputStream in = new java.net.URL(urldisplay).openStream();
mIcon11 = BitmapFactory.decodeStream(in);
} catch (Exception e) {
Log.e("Error", e.getMessage());
e.printStackTrace();
}
return mIcon11;
}
protected void onPostExecute(Bitmap result) {
mHeaderPicture.setImageBitmap(result);
}
}`
确保您在AndroidManifest.xml中设置了以下权限才能访问互联网。
<uses-permission android:name="android.permission.INTERNET" />