Question

我有一个包含字符串的列表列表。在经常使用各种正则表达式之后，我已将我想要用作分隔符@@@的内容插入到我的字符串中：

[['@@@this is part one and here is part two and here is part three and heres more and heres more'],
 ['this is part one@@@and here is part two and here is part three and heres more and heres more'],
 ['this is part one and here is part two@@@and here is part three and heres more and heres more']
 ['this is part one and here is part two and here is part three@@@and heres more and heres more']
 ['this is part one and here is part two and here is part three and heres more@@@and heres more']]

现在，我需要提出这个问题：

[['this is part one'],['and here is part two'],['and here is part three'], ['and heres more'], ['and heres more']]

到目前为止，我的尝试都是臃肿，黑客，而且一般都很难看。我发现自己分裂，组合和匹配。任何人都可以就这类问题推荐一些一般性建议，以及使用哪些工具来保持其可管理性？

编辑请注意！ and heres more确实在理想输出中出现两次！

Answer 1

我认为你实际上需要抓住@@@之后到下一个and或字符串结尾的所有字符。

>>> [[m] for x in l for m in re.findall(r'@@@(.*?)(?=\sand\b|$)', x[0])]
[['this is part one'], ['and here is part two'], ['and here is part three'], ['and heres more'], ['and heres more']]

基于Python中的分隔符拆分和组合文本

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