Question

我正在尝试在普及数据库上运行此查询

select cust_no,cust_name,sum(bvtotal) as Amount
from sales_history_header  
where cust_no is not null and number is not null and bvtotal > 1000 and in_date < 20140101
group by cust_no,cust_name
order by sum(bvtotal) desc;

如何排除那些包含in_date＆gt;的组结果？ 20140101在那里有子结果？

我的查询也提取了那些有in_date＆gt;的结果。 20140101

我做错了吗？

我得到的样本输出采用这种格式

cust_no     cust_name      amount
A             a1            500
B             b1            500
C             c1            1000

我想用cust_no＆＃39; A＆＃39;排除此记录。因为它在20140202中与in_date进行了交易

在我的原始数据中考虑我有像

这样的记录

cust_no     cust_name      amount    in_date
A             a1            100      20130203
A             a1            400      20130101
A             a1            1000     20140503

Answer 1

您需要根据一组ID排除所有记录。通常，您使用子查询执行此操作：

SELECT cust_no,
    cust_name,
    sum(bvtotal) AS Amount
FROM sales_history_header
WHERE cust_no IS NOT NULL
    AND number IS NOT NULL
    AND bvtotal > 1000
    AND cust_no NOT IN (
        SELECT cust_no 
        FROM sales_history_header 
        WHERE in_date >= 20140101 
            AND cust_no IS NOT NULL
    )
GROUP BY cust_no,
    cust_name
ORDER BY sum(bvtotal) DESC;

子查询的AND cust_no IS NOT NULL部分是为了避免NOT IN和NULL值出现问题。如果将其重写为NOT EXISTS相关子查询，则可能会有更好的性能，但根据我的经验，MySQL在这些方面非常糟糕。

另一种选择是更明确的自反连接方法（LEFT JOIN和过滤器，其中右表为空）但这有点......粗略的感觉？...因为你似乎允许cust_no为NULL而且因为它是一个聚合的查询，所以您觉得必须担心乘以行：

SELECT s1.cust_no,
    s1.cust_name,
    sum(s1.bvtotal) AS Amount
FROM sales_history_header s1
LEFT JOIN (
        SELECT cust_no
        FROM sales_history_header
        WHERE cust_no IS NOT NULL
            AND number IS NOT NULL
            AND bvtotal > 1000
            AND in_date >= 20140101) s2
    ON  s2.cust_no = s1.cust_no
WHERE s1.cust_no IS NOT NULL
    AND s1.number IS NOT NULL
    AND s1.bvtotal > 1000
    AND s2.cust_no IS NULL
GROUP BY cust_no,
    cust_name
ORDER BY sum(bvtotal) DESC;

结合LEFT JOIN的{{1}}是消除您不想要的记录的部分。

Answer 2

我认为你需要将日期常量指定为日期，除非你真的想要处理整数。

select cust_no,cust_name,sum(bvtotal) as Amount
from sales_history_header  
where cust_no is not null and number is not null and bvtotal > 1000 and in_date < '2014-01-01'
group by cust_no,cust_name
order by sum(bvtotal) desc;

Answer 3

我不明白你到底需要什么，

但似乎你混合了INT和DATE类型。

因此，如果您的in_date字段的类型为 DATE

select 
  cust_no,
  cust_name,
  sum(bvtotal) as Amount
from sales_history_header  
where cust_no is not null 
  and number is not null 
  and bvtotal > 1000 
  and in_date < DATE('2014-01-01')
group by cust_no,cust_name
order by sum(bvtotal) desc;

如果您的in_date字段的类型为 TIMESTAMP

select 
  cust_no,
  cust_name,
  sum(bvtotal) as Amount
from sales_history_header  
where cust_no is not null 
  and number is not null 
  and bvtotal > 1000 
  and in_date < TIMESTAMP('2014-01-01 00:00:00')
group by cust_no,cust_name
order by sum(bvtotal) desc;

普遍的查询与问题分组

3 个答案: