Question

我已经阅读了这篇帖子，但我仍然不知道发生了什么。

根据大多数JSON在线数据检查器，我的var“text”是有效的，但是当我执行解析时，它没有做任何事情。

以下是一个示例代码：

<!DOCTYPE html>
<html>
<body>

<h2>Create Object from JSON String</h2>

<p id="demo"></p>

<script>
var text = '{
"zipcodes": [
    {
        "zip": "22312",
        "city": "Alexandria",
        "state": "VA"
    },
    {
        "zip": "22030",
        "city": "Fairfax",
        "state": "VA"
    },
    {
        "zip": "22301",
        "city": "Tyson's Corner",
        "state": "VA"
    },
    {
        "zip": "20148",
        "city": "Ashburn",
        "state": "VA"
    }
]}';

obj = JSON.parse(text);
document.getElementById("demo").innerHTML =
obj.zipcodes[1].zip + " " + obj.zipcodes[1].city;
</script>

</body>
</html>

Answer 1

您有两个问题：

JavaScript不支持多行字符串而不用连续符号标记每一行（在行尾通过\）。我已经在我的例子中完成了这个，但是将JSON包含在一行中真的更容易。
您对字符串使用单引号，但您的字符串包含未转义的'。逃避它，你很好。

var text = '{ \
  "zipcodes": [\
    { \
      "zip": "22312", \
      "city": "Alexandria", \
      "state": "VA" \
    }, \
    { \
      "zip": "22030", \
      "city": "Fairfax", \
      "state": "VA" \
    }, \
    { \
      "zip": "22301", \
      "city": "Tyson\'s Corner", \
      "state": "VA" \
    }, \
    { \
      "zip": "20148", \
      "city": "Ashburn", \
      "state": "VA" \
    } \
  ]}';

obj = JSON.parse(text);
document.getElementById("demo").innerHTML =
obj.zipcodes[1].zip + " " + obj.zipcodes[1].city;

<div id='demo'></div>

Answer 2

您必须将json放在一行并转义'。

“泰森的角落”

http://jsbin.com/xumiba/1/edit?html,js,console,output

var text = '{ "zipcodes": [ { "zip": "22312", "city": "Alexandria", "state": "VA" }, { "zip": "22030", "city": "Fairfax", "state": "VA" }, { "zip": "22301", "city": "Tyson\'s Corner", "state": "VA" }, { "zip": "20148", "city":"Ashburn", "state": "VA" }]}';

Answer 3

你需要在每个字符串新行的末尾添加\并转义'字符。这样的事情会做：

var text = '{\
"zipcodes": [\
    {\
        "zip": "22312",\
        "city": "Alexandria",\
        "state": "VA"\
    },\
    {\
        "zip": "22030",\
        "city": "Fairfax",\
        "state": "VA"\
    },\
    {\
        "zip": "22301",\
        "city": "Tyson\'s Corner",\
        "state": "VA"\
    },\
    {\
        "zip": "20148",\
        "city": "Ashburn",\
        "state": "VA"\
    }\
]}';

obj = JSON.parse(text);

console.log(obj.zipcodes[1].zip + " " + obj.zipcodes[1].city);
document.getElementById("demo").innerHTML =
obj.zipcodes[1].zip + " " + obj.zipcodes[1].city;

这是一个jsfiddle链接：

http://jsfiddle.net/0retway7/

我无法使用Javascript使用JSON进行解析

3 个答案: