php pdo具有多个参数的搜索代码

时间:2015-03-11 15:38:53

标签: php mysql pdo

以下是我的代码......

我正在尝试使用php pdo中的多个参数创建搜索....使用多个if else条件...在单个查询...

PLZ帮助......做到这一点......我怎么能用php pdo做到这一点......

  <?php
$db=new PDO('mysql:host=localhost;dbname=circulation_scheme_prepaid','root','');
if(isset($_POST['Submit']))
{   
$result=$db->prepare('SELECT * FROM receipt_entry WHERE');
    if($_POST['book']!='')
    {
         $result->bindParam(':book',$_POST['book']);
    }    
$result->execute(); 
$data = $result->fetchAll();
}
?>

我想在上面编写代码..

<?php
require_once("includes/config.php");
if(isset($_POST['search']))
{   
    $sql = "SELECT * FROM properties WHERE";

    if($_POST['location']!='')
    {
        $location = $_POST['location'];
        $sql .= " location = '$location' AND";
    }

    if($_POST['purpose']!='')
    {
        $purpose = $_POST['purpose'];
        $sql .= " purpose = '$purpose' AND";
    }
    $sql = substr($sql, 0 ,-3); 

$query = mysql_query($sql);
while($row = mysql_fetch_array($query,MYSQL_ASSOC))
        {
            $rows[] = $row;
        }

}
?>

1 个答案:

答案 0 :(得分:0)

您可以尝试这样的事情:

if (isset($_POST['search'])) {
  $sql = 'SELECT * FROM properties';
  $where = array();
  $params = array();

  if (!empty($_POST['location'])) {
    $where[] = "location = :location";
    $params[':location'] = $_POST['location'];
  }

  if (!empty($_POST['purpose'])) {
    $where[] = "purpose = :purpose";
    $params[':purpose'] = $_POST['purpose'];
  }

  if(count($where) > 0)
      $sql .= ' WHERE ' . implode(' AND ', $where);

  $stmt = $db->prepare($sql);

  foreach($params as $param => $value) {
    $stmt->bindParam($param, $value);
  }

  $stmt->execute();
  $data = $stmt->fetchAll();

  print_r($data);
}