Question

表名 - scheme_master

column name - book_no2,receipt_no

表名 - book_issue

column name - book_no

表格名称 - book_return

column name - used_receipt

我只需要选择那些在图书发行表上创建图书的方案大师的那个receipt_no，以及book_return表中没有的receipt_no。

FOR EX -

scheme_master中的数据

Book_no2     receipt_no

1         -     10

1         -     11

2         -     14

2         -     15

3         -     18

3         -     19

DATE IN Book_issue表

Book_no

3

book        used_receipt

3               18

book_return表格中的数据

在上面的例子中，有3本书在方案主表1,2,3中用diff创建。收据OK。

但在书籍发行表中，我们只分配了第3册。

AND在Book return table中，我们只使用了收据18。

所以我需要从方案主表中选择所有只有第3册的第19号收据......

-plz有助于解决这个问题......

以下是我的查询，它运作正常......

但这需要花费大量时间来选择记录......

FOR EX -it需要超过6分钟才能从30条记录中获取...

  SELECT DISTINCT SM.receipt_no 
  FROM scheme_master SM 
  Inner join book_issue BI ON BI.book_no = SM.Book_no2  
  where 
  SM.receipt_no not in (select used_receipt from book_return)

Answer 1

希望这会对你有所帮助。

SELECT sm.receipt_no FROM scheme_master as sm, book_return as br
INNER JOIN book_issue as bi ON sm.book_no2 = bi.book_no
WHERE sm.receipt_no != br.used_receipt

Answer 2

我认为这就是你需要的......

SELECT        scheme_master.Book_no2, scheme_master.receipt_no 
FROM            book_return RIGHT OUTER JOIN
                         Book_issue ON book_return.book = Book_issue.Book_no RIGHT OUTER JOIN
                         scheme_master ON Book_issue.Book_no = scheme_master.Book_no2
WHERE        (Book_issue.Book_no IS NOT NULL) AND  scheme_master.receipt_no != book_return.used_receipt

第二个选项获取所有记录，即使没有与书籍相关的记录......

SELECT        scheme_master.Book_no2, scheme_master.receipt_no
FROM            scheme_master LEFT OUTER JOIN
                         Book_issue ON Book_issue.Book_no = scheme_master.Book_no2 LEFT OUTER JOIN
                         book_return ON book_return.book = Book_issue.Book_no
WHERE        (Book_issue.Book_no IS NOT NULL AND scheme_master.receipt_no <> book_return.used_receipt) OR
                         (book_return.used_receipt IS NULL)

最后 - 与你的例子类似 - 但运行起来并不多：

SELECT        DISTINCT sm.Book_no2, sm.receipt_no
FROM            scheme_master sm LEFT OUTER JOIN
                         Book_issue bi ON bi.Book_no = sm.Book_no2 LEFT OUTER JOIN
                         book_return br ON br.book = sm.Book_no2
WHERE         sm.receipt_no NOT IN (SELECT DISTINCT used_receipt FROM book_return)

sql查询从两个表中过滤数据

2 个答案: