我想将JSON字符串转换为android Bundle。要求就是直接从服务器将参数作为JSON而不是bundle传递给活动。如何将JSON字符串转换为Android Bundle?如果可能,请提供抽象代码。
答案 0 :(得分:14)
public static Bundle jsonStringToBundle(String jsonString){
try {
JSONObject jsonObject = toJsonObject(jsonString);
return jsonToBundle(jsonObject);
} catch (JSONException ignored) {
}
return null;
}
public static JSONObject toJsonObject(String jsonString) throws JSONException {
return new JSONObject(jsonString);
}
public static Bundle jsonToBundle(JSONObject jsonObject) throws JSONException {
Bundle bundle = new Bundle();
Iterator iter = jsonObject.keys();
while(iter.hasNext()){
String key = (String)iter.next();
String value = jsonObject.getString(key);
bundle.putString(key,value);
}
return bundle;
}
答案 1 :(得分:9)
这已经很晚了,但也许有人找到了这个帖子:
/** Convert a JSON object to a Bundle that can be passed as the extras of
* an Intent. It passes each number as a double, and everything else as a
* String, arrays of those two are also supported. */
public static Bundle fromJson(JSONObject s) {
Bundle bundle = new Bundle();
for (Iterator<String> it = s.keys(); it.hasNext(); ) {
String key = it.next();
JSONArray arr = s.optJSONArray(key);
Double num = s.optDouble(key);
String str = s.optString(key);
if (arr != null && arr.length() <= 0)
bundle.putStringArray(key, new String[]{});
else if (arr != null && !Double.isNaN(arr.optDouble(0))) {
double[] newarr = new double[arr.length()];
for (int i=0; i<arr.length(); i++)
newarr[i] = arr.optDouble(i);
bundle.putDoubleArray(key, newarr);
}
else if (arr != null && arr.optString(0) != null) {
String[] newarr = new String[arr.length()];
for (int i=0; i<arr.length(); i++)
newarr[i] = arr.optString(i);
bundle.putStringArray(key, newarr);
}
else if (!num.isNaN())
bundle.putDouble(key, num);
else if (str != null)
bundle.putString(key, str);
else
System.err.println("unable to transform json to bundle " + key);
}
return bundle;
}
答案 2 :(得分:-1)
jaffa的答案很好,但是它仅适用于depth = 1的JSON对象。我通过添加对嵌套对象的支持对其进行了改进。
private static Bundle jsonStringToBundle(String jsonString) {
try {
JSONObject jsonObject = new JSONObject(jsonString);
return jsonToBundle(jsonObject);
} catch (JSONException ignored) {}
return null;
}
private static Bundle jsonToBundle(JSONObject jsonObject) throws JSONException {
Bundle bundle = new Bundle();
Iterator iter = jsonObject.keys();
while (iter.hasNext()) {
String key = (String)iter.next();
String value = jsonObject.getString(key);
Bundle bundleVal = jsonStringToBundle(value);
if (bundleVal != null) {
bundle.putBundle(key, bundleVal);
} else {
bundle.putString(key, value);
}
}
return bundle;
}
用法:
Bundle bundle = jsonStringToBundle("{...}");
答案 3 :(得分:-6)
快速SSCCEE
<强>的A.class 强>
// key for bundle ...
public static final JSON_STRING = "jsonString";
Intent intent = new Intent(A.this, B.class);
Bundle bundle = new Bundle();
bundle.putString(JSON_STRING,json.toString());
intent.putExtras(bundle);
startActivity(intent);
然后在 B.class ...
Intent intent = getIntent();
Bundle extras = intent.getExtras();
String jsonString = extras.getString(A.JSON_STRING);