Question

我使用WakefulBroadcastReceiver

中的方法设置AlarmManager

public class AlarmManagerBroadcastReceiver extends WakefulBroadcastReceiver {
public static final String WAKEUP = "wakeup";

@Override
public void onReceive(Context context, Intent intent) {
    Utils.PrintInfo("Alarm received!");

    try {
        Intent newIntent = new Intent(context, AlarmWakefulService.class);
        startWakefulService(context, newIntent);
    } catch (Exception e) {
        Toast.makeText(
                context,
                "There was an error somewhere, but we still received an alarm",
                Toast.LENGTH_SHORT).show();
        e.printStackTrace();
    }
}

public void setOnetimeTimer(Context context, long triggerAtMillis) {

    AlarmManager am = (AlarmManager) context
            .getSystemService(Context.ALARM_SERVICE);
    Intent intent = new Intent(context, AlarmManagerBroadcastReceiver.class);
    intent.putExtra(WAKEUP, true);
    PendingIntent pi = PendingIntent.getBroadcast(context, 0, intent, 0);
    //am.setExact(AlarmManager.ELAPSED_REALTIME_WAKEUP, triggerAtMillis, pi);
    am.set(AlarmManager.RTC_WAKEUP, triggerAtMillis, pi);
}
}

和我的AlarmWakefulService

public class AlarmWakefulService extends IntentService {
public AlarmWakefulService() {
    super("AlarmWakefulService");
}

@Override
protected void onHandleIntent(Intent intent) {

    Context context = getApplicationContext();

    PowerManager pm = (PowerManager) context
            .getSystemService(Context.POWER_SERVICE);
    WakeLock wakeLock = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK
            | PowerManager.ACQUIRE_CAUSES_WAKEUP
            | PowerManager.ON_AFTER_RELEASE, "WakeLockLauncher");
    wakeLock.acquire();

    Utils.PrintInfo("AlarmManagerBroadcastReceiver, Completed service @ "
            + SystemClock.elapsedRealtime());

    Intent newIntent = new Intent(context, AlarmReceiveActivity.class);
    newIntent.putExtra("ALARM_TIME", intent.getStringExtra("ALARM_TIME"));
    newIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    context.startActivity(newIntent);

    wakeLock.release();
    wakeLock = null;

    AlarmManagerBroadcastReceiver.completeWakefulIntent(intent);
}
}

两者都在清单文件

中

<receiver android:name="com.xxxx.alarm.AlarmManagerBroadcastReceiver" ></receiver> <service android:name="com.xxxx.alarm.AlarmWakefulService" />

我也得到了许可

    <uses-permission android:name="com.android.alarm.permission.SET_ALARM" />
<uses-permission android:name="android.permission.SET_ALARM" />
<uses-permission android:name="android.permission.WAKE_LOCK" />

并不总是闹钟唤醒设备，有时我必须解锁设备才能进行闹钟呼叫，我也尝试使用ELAPSED_REALTIME_WAKEUP而不是RTC_WAKEUP设置它（当我将RTC_WAKEUP更改为{时{1}}我改变了计算ELAPSED_REALTIME_WAKEUP）的方法，但后来甚至更糟，设备没有更频繁地唤醒。

还有其他方法可以将设备从深度睡眠中唤醒吗？

Answer 1

您的接收器需要在远程进程上运行。这允许系统唤醒该过程。在你的清单中使用它：

<receiver android:process=":remote" android:name="com.maxcom.alarm.AlarmManagerBroadcastReceiver" />

我刚刚向接收者添加了android:process=":remote"声明。

WakefulBroadcastReceiver不会将设备从深度睡眠中唤醒

1 个答案: