Question

我一直在尝试创建upload.php脚本但是条件似乎不起作用，PHP无法将上传的文件移动到文件夹上传。

下面的Apache2日志输出

PHP Warning:  move_uploaded_file(): The second argument to copy() function cannot be a directory in /var/www/html/upload.php on line 18, referer: http://192.168.0.110/stream.php

PHP Warning:  move_uploaded_file(): Unable to move '/tmp/phpC34Agu' to '/var/www/html/upload/' in /var/www/html/upload.php on line 18, referer: http://192.168.0.110/stream.php

Upload.php代码

   <?php
$target_path = "/var/www/html/upload/";
$target = $target_path . basename($_FILES['uploadedfile']['name'][0] );
    if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'] [0], $target_path))
     { 
    echo "The file ". basename( $_FILES['uploadefile']['name'] [0]). " has been uploaded"; 
   } 
    else {
 echo "Sorry, there was a problem uploading your file."; 
     }
   ?>

我还希望php能够直接执行这个ffmpeg命令，但我不确定在哪里插入它。

FFMPEG命令

ffmpeg -re -i uploadedfile.name -vcodec copy -f mpegts udp://239.1.1.1:5000

感谢您的帮助。

亲切的问候，

Mark Couto

Answer 1

您需要指定文件的INDEX KEY ：

$ _ FILES [＆＃39;上传＆＃39;] [＆＃39; tmp_name的值＆＃39;]的 [0]

$target = $target . basename($_FILES["fileToUpload"]["name"][0]); if(move_uploaded_file($_FILES['uploaded']['tmp_name'][0], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name'][0]). " has been uploaded"; }

Answer 2

这是问题所在的代码部分

      if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))

$ _ FILES ['上传'] 应为$ _FILES ['FileToUpload']

试试这个

      if(move_uploaded_file($_FILES['FileToUpload']['tmp_name'], $target))

＆LT = http://php.net/manual/en/features.file-upload.post-method.php

PHP无法移动上传的文件

2 个答案: