Question

是否可以在javascript中的客户端上实现一个函数，以便像这样使用它：

var county = get_county(zip_code);

我的意思是可以通过脚本在线完成吗？或者我必须挖一些数据库？或者我必须买它？

任何帮助表示赞赏！

P.S。
在Dyrandz Famador的帮助下，我为GAS做了这个功能：

function get_county(zip) {
 var county, response, result, adresses, i, j, n, type;
 response = Maps.newGeocoder().geocode(zip);
 for (i = 0; i < response.results.length; i++) {
   result = response.results[i];
   adresses = result.address_components;
   n = adresses.length;
   for (j=0;j<n;j++) {
     type = adresses[j].types[0];
     if (type == 'locality') county = (adresses[j].long_name);
     if (type == 'administrative_area_level_2')   {county =(adresses[j].long_name);}
   }
 }
 return (county);
}

Answer 1

您可以使用Google Maps API从邮政编码中获取地点

Google提供了许多API，其中包括Maps API。在这个例子中我们将显示使用邮政编码打到Google所需的所有代码以城市，州和国家的形式获得位置。

首先要做的是参考Google的Map API：

<script language="javascript" src="https://maps.google.com/maps/api/js?sensor=false"></script>

接下来是一个用于输入邮政编码的小表格：

<form>
zip: <input type="text" name="zip" value="46032"> <a href="#" onclick="getLocation()">Get Address</a>
</form>

你可以看到我有一个激活名为“getLocation()”的函数的链接 - 下面你会找到该函数和相关代码：

...
<script language="javascript">
function getLocation(){
  getAddressInfoByZip(document.forms[0].zip.value);
}

function response(obj){
  console.log(obj);
}
function getAddressInfoByZip(zip){
  if(zip.length >= 5 && typeof google != 'undefined'){
    var addr = {};
    var geocoder = new google.maps.Geocoder();
    geocoder.geocode({ 'address': zip }, function(results, status){
      if (status == google.maps.GeocoderStatus.OK){
        if (results.length >= 1) {
      for (var ii = 0; ii < results[0].address_components.length; ii++){
        var street_number = route = street = city = state = zipcode = country = formatted_address = '';
        var types = results[0].address_components[ii].types.join(",");
        if (types == "street_number"){
          addr.street_number = results[0].address_components[ii].long_name;
        }
        if (types == "route" || types == "point_of_interest,establishment"){
          addr.route = results[0].address_components[ii].long_name;
        }
        if (types == "sublocality,political" || types == "locality,political" || types == "neighborhood,political" || types == "administrative_area_level_3,political"){
          addr.city = (city == '' || types == "locality,political") ? results[0].address_components[ii].long_name : city;
        }
        if (types == "administrative_area_level_1,political"){
          addr.state = results[0].address_components[ii].short_name;
        }
        if (types == "postal_code" || types == "postal_code_prefix,postal_code"){
          addr.zipcode = results[0].address_components[ii].long_name;
        }
        if (types == "country,political"){
          addr.country = results[0].address_components[ii].long_name;
        }
      }
      addr.success = true;
      for (name in addr){
          console.log('### google maps api ### ' + name + ': ' + addr[name] );
      }
      response(addr);
        } else {
          response({success:false});
        }
      } else {
        response({success:false});
      }
    });
  } else {
    response({success:false});
  }
}
</script>

...

就是这样 - 在Chrome中打开控制台并在输入不同的邮政编码时注意输出。

从这里得到它： http://rickluna.com/wp/2012/09/using-the-google-maps-api-to-get-locations-from-zip-codes/

Answer 2

你需要知道zip_code和country的映射，

我为此找到了一个github项目：

https://github.com/jgoodall/us-maps

一旦你通过指令获得json映射，就可以实现你想要的功能。

Answer 3

这是来自美国政府的一个很好的地理数据库API：
https://www.sba.gov/about-sba/sba-performance/sba-data-store/web-service-api/us-city-and-county-web-data-api#county-state

API会生成所有县和州信息，但它似乎没有包含邮政编码。使用Google Geocoding API可能会更容易。

Answer 4

这是您可以从几乎任何位置输入中获取地址，城市，州和/或邮政编码的一种方式，例如Santa Monica, CA或90405。请记住，除非您在请求中非常具体，否则您无法始终获得所有这些变量。

function getLocationInfo(){

    var location = $('#location').val();
    var geocoder = new google.maps.Geocoder();

    geocoder.geocode({ 'address': location }, function (result, status) {

    var address = '';
    var streetNumber = '';
    var streetName = '';
    var cityName = '';
    var stateName = '';
    var zipCode = '';

    var addressComponent = result[0]['address_components'];

    // find street number

    var streetNumberQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('street_number', x.types) != -1;
    });

    if (streetNumberQueryable.length) {
        streetNumber = streetNumberQueryable[0]['long_name'];
    }

    // find street name

    var streetNameQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('route', x.types) != -1;
    });

    if (streetNameQueryable.length) {
        streetName = streetNameQueryable[0]['long_name'];
    }

    // find city data

    var cityQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('locality', x.types) != -1;
    });

    if (cityQueryable.length) {
        cityName = cityQueryable[0]['long_name'];
    }

    // find state data

    var stateQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('administrative_area_level_1', x.types) != -1;
    });

    if (stateQueryable.length) {
        stateName = stateQueryable[0]['long_name'];
    }

    // find zip data

    var zipQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('postal_code', x.types) != -1;
    });

    if (zipQueryable.length) {
        zipCode = zipQueryable[0]['long_name'];
    }

    address = streetNumber + ' ' + streetName;

    console.log(address);
    console.log(cityName);
    console.log(stateName);
    console.log(zipCode);

    });

}

如何通过邮政编码确定美国县？

4 个答案: