在尝试计算两个日期之间的天数时,我注意到波纹管代码中的错误。 2月份没有权利,
这是代码,
public class NewClass {
public int numberOfDays(String fromDate,String toDate)
{
java.util.Calendar cal1 = new java.util.GregorianCalendar();
java.util.Calendar cal2 = new java.util.GregorianCalendar();
StringBuffer sBuffer = new StringBuffer(fromDate);
String yearFrom = sBuffer.substring(6,10);
String monFrom = sBuffer.substring(0,2);
String ddFrom = sBuffer.substring(3,5);
int intYearFrom = Integer.parseInt(yearFrom);
int intMonFrom = Integer.parseInt(monFrom);
int intDdFrom = Integer.parseInt(ddFrom);
cal1.set(intYearFrom, intMonFrom, intDdFrom);
StringBuffer sBuffer1 = new StringBuffer(toDate);
String yearTo = sBuffer1.substring(6,10);
String monTo = sBuffer1.substring(0,2);
String ddTo = sBuffer1.substring(3,5);
int intYearTo = Integer.parseInt(yearTo);
int intMonTo = Integer.parseInt(monTo);
int intDdTo = Integer.parseInt(ddTo);
cal2.set(intYearTo, intMonTo, intDdTo);
int days = daysBetween(cal1.getTime(),cal2.getTime());
return days;
}
public int daysBetween(Date d1, Date d2)
{
return (int)( (d2.getTime() - d1.getTime()) / (1000 * 60 * 60 * 24));
}
public static void main(String[] args) throws ParseException {
String s1 = "02-28-2015";
String s2 = "03-01-2015";
int num=numberOfDays(s1, s2);
System.out.println(num);
}
}
如果我们给出varialbe s1和s2的上述日期,结果是4.但答案是错误的 因为2015年2月只有28天。
我认为问题是这个功能部分(1000 * 60 * 60 * 24)
如果有人知道如何处理此问题,请更新此代码或给我一些帮助!
答案 0 :(得分:0)
不要尝试使用两次之间的毫秒差来计算差异,只有很多特性与日期/时间计算可能会导致各种错误。
相反,保存自己(很多)时间并使用专用库
LocalDate start = LocalDate.of(2015, Month.JANUARY, 1);
LocalDate end = LocalDate.now();
long days = ChronoUnit.DAYS.between(start, end);
System.out.println(days);
哪个输出69
DateTime startDate = new DateTime(2015, DateTimeConstants.JANUARY, 1, 0, 0);
DateTime endDate = new DateTime();
Days d = Days.daysBetween(startDate, endDate);
int days = d.getDays();
System.out.println(days);
哪个输出69