我正在制作RPG游戏,用户可以登录并保存和加载数据。我可以登录并保存。但是,当我想加载数据时,我很难加载它。
我将仅发布必要的代码(PHP代码(Load.php)):
<?PHP
$Username = $_POST['Username'];
$Location = $_POST['Location'];
$Gold = $_POST['Gold'];
$Level = $_POST['Level'];
$Attack = $_POST['Attack'];
$Defense = $_POST['Defense'];
$MagicDefense = $_POST['MagicDefense'];
$Evasion = $_POST['Evasion'];
$Health = $_POST['Health'];
$MaxHealth = $_POST['MaxHealth'];
$Mana = $_POST['Mana'];
$MaxMana = $_POST['MaxMana'];
$Exp = $_POST['Exp'];
$NextExp = $_POST['NextExp'];
$AcceptedChiefQuest = $_POST['AcceptedChiefQuest'];
$AddedChiefQuest = $_POST['AddedChiefQuest'];
$con = mysql_connect("SERVER_NAME","DATABASE_NAME","PASSWORD") or ("Cannot connect!" . mysql_error());
if (!$con)
die('Could not connect: ' . mysql_error());
mysql_select_db("DATABASE_NAME" , $con) or die ("Could not load the database" . mysql_error());
$check = mysql_query("SELECT * FROM Information WHERE `Username` = '".$Username."'");
$numrows = mysql_num_rows($check);
if ($numrows > 0)
{
while($row = mysql_fetch_assoc($check))
{
$Username = $row['Username'];
$Location = $row['Location'];
$Gold = $row['Gold'];
$Level = $row['Level'];
$Attack = $row['Attack'];
$Defense = $row['Defense'];
$MagicDefense = $row['MagicDefense'];
$Evasion = $row['Evasion'];
$Health = $row['Health'];
$MaxHealth = $row['MaxHealth'];
$Mana = $row['Mana'];
$MaxMana = $row['MaxMana'];
$Exp = $row['Exp'];
$NextExp = $row['NextExp'];
$AcceptedChiefQuest = $row['AcceptedChiefQuest'];
$AddedChiefQuest = $row['AddedChiefQuest'];
echo $Location;
}
die("Successfully Loaded!");
}
else
{
die ("Data does not exist!");
}
?>
在这里我通过Unity中的脚本访问它(问题所在的必要代码):
IEnumerator LoadCoroutine(WWW _www)
{
yield return _www;
if (_www.error == null)
{
message = _www.text;
if (_www.text == "Successfully Loaded!")
{
// Below code from this line, never gets executed (if and else if statement)
// The `GameManager.CurrentLocation` appear as default value
if (_www.text == "Village")
{
GameManager.CurrentLocation = "Village";
GameManager.Loader = 1;
}
else if (_www.text == "Yein Plain")
{
GameManager.CurrentLocation = "Yein Plain";
GameManager.Loader = 4;
}
// Below code from this line will gets executed.
message = "Successfully Loaded.";
mainMenu = false;
yield return new WaitForSeconds(3);
Reset();
GameManager.LoadLevel("Loading Scene");
}
else if (_www.text == "Data does not exist!")
{
message = "Data does not exist";
clickedLoadGame = false;
}
else if (_www.text == "Saved data does not match!")
{
message = "Saved data does not match";
clickedLoadGame = false;
}
}
else
{
message = "Error while trying to connect to the server.\nMessage: " + _www.error;
clickedLoadGame = false;
}
}
当我Debug.Log
message
时,它看起来像这样:VillageSuccessfullyLoaded!
,它永远不会显示为Village
或Yein Plain
。似乎PHP代码中的echo
和die
组合在一起。
我的问题是,如何从php而不是其他代码中检索$Location
?因此,它只返回Village
或Yein Plain
。
真的很感激你的回答!
非常感谢
答案 0 :(得分:1)
更改
die("Successfully Loaded!");
到
die();
然后:
if (_www.text == "Data does not exist!")
{
message = "Data does not exist";
clickedLoadGame = false;
}
else if (_www.text == "Saved data does not match!")
{
message = "Saved data does not match";
clickedLoadGame = false;
}
else
{
if (_www.text == "Village")
{
GameManager.CurrentLocation = "Village";
GameManager.Loader = 1;
}
else if (_www.text == "Yein Plain")
{
GameManager.CurrentLocation = "Yein Plain";
GameManager.Loader = 4;
}
message = "Successfully Loaded.";
mainMenu = false;
yield return new WaitForSeconds(3);
Reset();
GameManager.LoadLevel("Loading Scene");
}