Question

我正在尝试从multipart / form获取文件。为此我使用的是HttpRequestHandler

这是我的班级

public class ResponseHandler implements HttpRequestHandler {

@Override
public void handle(HttpRequest request, HttpResponse response,
        HttpContext httpContext) throws HttpException, IOException {
    InputStream is = ((HttpEntityEnclosingRequest) request)
            .getEntity().getContent();
    //how extract file here 
   //stream consist other form data 

}
public void saveImage(InputStream input,File file){
try {

        OutputStream output = null;
    try {
        output = new FileOutputStream(file);
    } catch (FileNotFoundException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    try {
        try {
            final byte[] buffer = new byte[1024];
            int read;

            while ((read = input.read(buffer)) != -1)
                output.write(buffer, 0, read);

            output.flush();
        } finally {
            output.close();
        }
    } catch (Exception e) {
        e.printStackTrace();
    }
} finally {

   }
  }
}

这是multipart / form

<form action="upload" method="post" enctype="multipart/form-data">
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>

我能够获得包含文件和表单数据的输入流。所以问题是如何从inputream中提取文件和其他数据。

如果我保存输入流，则文件看起来像是：

------ WebKitFormBoundaryzxxA1lnrlIK6B9ob 内容处理：表格数据; NAME = “fileToUpload”;文件名= “A.JPG” 内容类型：image / jpeg

ÿØÿàÿÀÿÀÿÀ234gy2ÿØÿÿÿÀÿÀÿÀ234gy2ÿÿÿàÿÀÿÀÿÀ234gy27ÿØÿàÀÿÀÿÀ234gy2ÿØÿàÿÀÿÀÿÀ234gy2ÿØÿàÿÀÿÀÿÀ234gy2 ..............................

从multipart / form获取文件HttpRequestHandler

0 个答案: