仅由一个名称选择的多个值的副本:以逗号分隔

时间:2015-03-11 01:21:06

标签: sql-server sql-server-2008

请参考下图:

MSSQL server 2008 QUERY MULTIPLE VALUES IN COMMA SEPARATED VALUES BY ONLY ONE SELECTED NAME

2 个答案:

答案 0 :(得分:1)

创建你的表taro:

SELECT * INTO taro
FROM 
(
    SELECT 1111 AS [C no.], 'ken' AS [Name], 'shiro' AS Item, '3/3/2000 12:22' AS [Date], '$25' AS Amount
    UNION ALL
    SELECT 1111 AS [C no.], 'ken' AS Name, 'aeshte' AS Item, '3/3/2000 12:22' AS [Date], '$25' AS Amount
    UNION ALL 
    SELECT 1111 AS [C no.], 'ken' AS Name, 'taro' AS Item, '3/3/2000 12:22' AS [Date], '$25' AS Amount
    UNION ALL
    SELECT 2222,'yakumo','tesen','3/4/2000 12:22','$22'
    UNION ALL
    SELECT 2222,'yakumo','aoie','3/4/2000 12:22','$22'
    UNION ALL
    SELECT 3333,'kage','manase','3/5/2000 12:22','$21'
) A

按列对其进行分组,并将项目放在一起,以逗号分隔

SELECT
    [C No.],
    Name,
    [Date],
    Amount,
    STUFF((
    SELECT ',' + A.Item
    FROM taro A
    WHERE   A.[C no.] = B.[C no.]
    AND     A.Name = B.Name
    AND     A.[Date] = B.[Date]
    AND     A.[Amount] = B.[Amount]
    ORDER BY item
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)'),1,1,'') AS ItemValue
FROM taro B
GROUP BY [C No.],Name,[Date],Amount

结果:

C No.       Name   Date           Amount ItemValue
----------- ------ -------------- ------ --------------------
1111        ken    3/3/2000 12:22 $25    aeshte,shiro,taro
2222        yakumo 3/4/2000 12:22 $22    aoie,tesen
3333        kage   3/5/2000 12:22 $21    manase

答案 1 :(得分:0)

DECLARE @Table1 TABLE(CNo INT, name nvarchar(20), item nvarchar(20),Date datetime, Value INT)
INSERT INTO @Table1 VALUES  (1111,'ken','shiro', GETDATE(), 25),
                        (1111,'ken', 'aeshte', GETDATE(), 25),
                        (1111,'ken', 'taro', GETDATE(), 25),
                        (2222,'yakumo', 'tesen', GETDATE(), 25),
                        (2222,'yakumo', 'aole', GETDATE(), 25),
                        (3333,'kage', 'manase', GETDATE(), 25)


SELECT  CNo 
   ,STUFF((SELECT ', ' + CAST((item) AS VARCHAR(10)) [text()]
     FROM @Table1 
     WHERE CNo = t.CNo  and date = t.Date and Value = t.Value and name = t.name
     FOR XML PATH(''), TYPE)
    .value('.','NVARCHAR(MAX)'),1,2,' ') Item, 
    date, value, name
FROM @Table1 t
GROUP BY CNo,  Date, value, name