是否可以使用Java加载类并“伪造”类的包名称/规范名称?我尝试这样做,显而易见的方法,但我在ClassDefNotFoundException
中得到了“类名不匹配”的消息。
我这样做的原因是我正在尝试加载在默认包中编写的API,以便我可以直接使用它而无需使用反射。代码将在表示包和包名称导入的文件夹结构中针对类进行编译。即:
./com/DefaultPackageClass.class
// ...
import com.DefaultPackageClass;
import java.util.Vector;
// ...
我目前的代码如下:
public Class loadClass(String name) throws ClassNotFoundException {
if(!CLASS_NAME.equals(name))
return super.loadClass(name);
try {
URL myUrl = new URL(fileUrl);
URLConnection connection = myUrl.openConnection();
InputStream input = connection.getInputStream();
ByteArrayOutputStream buffer = new ByteArrayOutputStream();
int data = input.read();
while(data != -1){
buffer.write(data);
data = input.read();
}
input.close();
byte[] classData = buffer.toByteArray();
return defineClass(CLASS_NAME,
classData, 0, classData.length);
} catch (MalformedURLException e) {
throw new UndeclaredThrowableException(e);
} catch (IOException e) {
throw new UndeclaredThrowableException(e);
}
}
答案 0 :(得分:15)
As Pete mentioned,这可以使用ASM字节码库完成。实际上,该库实际上附带了一个专门用于处理这些类名重新映射(RemappingClassAdapter
)的类。以下是使用此类的类加载器示例:
public class MagicClassLoader extends ClassLoader {
private final String defaultPackageName;
public MagicClassLoader(String defaultPackageName) {
super();
this.defaultPackageName = defaultPackageName;
}
public MagicClassLoader(String defaultPackageName, ClassLoader parent) {
super(parent);
this.defaultPackageName = defaultPackageName;
}
@Override
public Class<?> loadClass(String name) throws ClassNotFoundException {
byte[] bytecode = ...; // I will leave this part up to you
byte[] remappedBytecode;
try {
remappedBytecode = rewriteDefaultPackageClassNames(bytecode);
} catch (IOException e) {
throw new RuntimeException("Could not rewrite class " + name);
}
return defineClass(name, remappedBytecode, 0, remappedBytecode.length);
}
public byte[] rewriteDefaultPackageClassNames(byte[] bytecode) throws IOException {
ClassReader classReader = new ClassReader(bytecode);
ClassWriter classWriter = new ClassWriter(classReader, 0);
Remapper remapper = new DefaultPackageClassNameRemapper();
classReader.accept(
new RemappingClassAdapter(classWriter, remapper),
0
);
return classWriter.toByteArray();
}
class DefaultPackageClassNameRemapper extends Remapper {
@Override
public String map(String typeName) {
boolean hasPackageName = typeName.indexOf('.') != -1;
if (hasPackageName) {
return typeName;
} else {
return defaultPackageName + "." + typeName;
}
}
}
}
为了说明,我创建了两个类,这两个类都属于默认包:
public class Customer {
}
和
public class Order {
private Customer customer;
public Order(Customer customer) {
this.customer = customer;
}
public Customer getCustomer() {
return customer;
}
public void setCustomer(Customer customer) {
this.customer = customer;
}
}
这是Order
之前的列表任何重新映射:
> javap -private -c Order Compiled from "Order.java" public class Order extends java.lang.Object{ private Customer customer; public Order(Customer); Code: 0: aload_0 1: invokespecial #10; //Method java/lang/Object."":()V 4: aload_0 5: aload_1 6: putfield #13; //Field customer:LCustomer; 9: return public Customer getCustomer(); Code: 0: aload_0 1: getfield #13; //Field customer:LCustomer; 4: areturn public void setCustomer(Customer); Code: 0: aload_0 1: aload_1 2: putfield #13; //Field customer:LCustomer; 5: return }
这是重新映射后Order
的列表(使用com.mycompany
作为默认包):
> javap -private -c Order Compiled from "Order.java" public class com.mycompany.Order extends com.mycompany.java.lang.Object{ private com.mycompany.Customer customer; public com.mycompany.Order(com.mycompany.Customer); Code: 0: aload_0 1: invokespecial #30; //Method "com.mycompany.java/lang/Object"."":()V 4: aload_0 5: aload_1 6: putfield #32; //Field customer:Lcom.mycompany.Customer; 9: return public com.mycompany.Customer getCustomer(); Code: 0: aload_0 1: getfield #32; //Field customer:Lcom.mycompany.Customer; 4: areturn public void setCustomer(com.mycompany.Customer); Code: 0: aload_0 1: aload_1 2: putfield #32; //Field customer:Lcom.mycompany.Customer; 5: return }
正如您所看到的,重新映射已将所有Order
引用更改为com.mycompany.Order
,并将所有Customer
引用更改为com.mycompany.Customer
。
这个类加载器必须加载以下任何类:
答案 1 :(得分:1)
你应该能够使用ASM来解决问题,尽管在构建时而不是在加载时更容易重命名一次。
答案 2 :(得分:0)
将API从默认包中移动到更合理的位置可能会更容易吗?听起来你无法访问源代码。我不确定包是否被编码到类文件中,所以简单地移动API类可能值得一试。否则,像JAD这样的Java反编译器通常做得很好,所以你可以在反编译源中更改包名并再次编译。