Question

我正在构建一个小程序，以显示一组人的一些细节。可以选择更新详细信息。但是，视图不会呈现更新：

这是我的server.js：

var express= require("express"),
bodyparser= require("body-parser");

var app= express();

app.use(express.static(__dirname+ "/public"));
app.use(bodyparser.json());

app.get("/", function(req, res){
    res.render("index.jade");
});

app.listen(3002);

我的index.jade是：

doctype html

link(rel="stylesheet", href="backbui.css")

#main

script(src= "jquery.js")
script(src= "underscore.js")
script(src= "backbone.js")
script(src= "laconic.js")
script(src= "moment.js")
script(src= "backbui.js")
script(src= "theapp.js")

我的theapp.js文件是：

var Person= Backbone.Model.extend({}),
People= Backbone.Collection.extend({});

var Genders= new Backbone.Collection(
        [
             {name: "Female", id: 1},
             {name: "Male", id: 0}
]);

var people= new People([
            {name: "John Doe", gender: Genders.get(0), birthday:
             new Date(1990, 5, 15), married: false},
            {name: "Jane Smith", gender: Genders.get(1), birthday:
             new Date(1985, 10, 10), married: true},
            {name: "Tom Smith", gender: Genders.get(0), birthday: 
             new Date(1980, 1, 20), married: true},
            {name: "Sally Fox", gender: Genders.get(1), birthday: 
             new Date(1998, 7, 31), married: false}
]);

var table= new Backbone.UI.TableView({
    model: people,  // collection can also be passed
    columns: [
        {title: "Name", content: "name"},
        {title: "Gender", content: "gender", 
         format: function(model){ return model.get("name"); }},
        {title: "Birthday", content: "birthday",
         format: function(date){ return date.toString(); }},
        {title: "Married", content: "married",
         format: function(married){ return married? "yes": "no"; }}
    ]
}); 

var sally= people.models[3];

var textbox= new Backbone.UI.TextField({
    model: sally,
    content: "name",
});

var radios= new Backbone.UI.RadioGroup({
    model: sally,
    content: "gender",
    alternatives: Genders,
    altLabelContent: "name",
});

var Appview= Backbone.View.extend({
    el: "#main",

    render: function(){
            this.$el.append(table.render().el);
            this.$el.append(textbox.render().el);
            this.$el.append(radios.render().el);
            return this;
    }
});

new Appview().render();

我想看到表格中第4个名字的实时更新。当我在文本框区域进行更改时，Sally Fox。同样地，当我在单选按钮上进行更改时，我希望看到Sally Fox的表性别发生变化。

基本上我希望我的Backbone.TableView能够监听Backbone.UI.RadioGroup和Backbone.UI.TextField等其他Backbone.UI小部件所做的更改

Answer 1

你正走在正确的道路上。在视图中添加侦听器以侦听people集合发生更改的时间。个别模型的变化（即sally）也会在整个集合中冒出来。

我对Backbone.UI不太熟悉，但改变会是这样的：

// Make the table listen to changes in the passed-in collection & re-render
// when needed
var table= new Backbone.UI.TableView({
    model: people,  // collection can also be passed
    columns: [
        {title: "Name", content: "name"},
        {title: "Gender", content: "gender", 
         format: function(model){ return model.get("name"); }},
        {title: "Birthday", content: "birthday",
         format: function(date){ return date.toString(); }},
        {title: "Married", content: "married",
         format: function(married){ return married? "yes": "no"; }}
    ],

    initialize: function() {
        // When a change event happens to the model/collection, re-render
        this.listenTo(model, 'change', this.render);
    }
});

您会对要对数据更改做出反应的其他视图执行类似的操作。关键是让视图共享您正在更改的模型/集合的相同实例，然后监听特定的更改。

如果这不能帮助您，请发表评论和/或JSFiddle，我们可以通过这种方式取得进展。

Answer 2

虽然Peter（上图）给出的答案也是正确的，但我们也可以直接在backbone-ui.js库文件中进行更改：

在tableview的initialize方法内部（在文件backbone-ui.js中搜索tableview，找到它的初始化函数）添加：

this.model.on("change", this.render, this);

你会没事的。（您可能希望在backbone-ui.js文件的list属性的initialize方法中添加相同的行以获取列表的响应视图）

Backbone.View没有响应Backbone.UI

2 个答案: