Question

我有一个这样的课程：

class ControlVocabulary(models.Model):
    definition = models.TextField()
    term = models.CharField(primary_key=True, max_length=255)

    class Meta:
        abstract = True

为什么我不能使用＆＃39;定义＆＃39;在一个儿童班里面？有没有办法可以做到这一点？

class ActionType(ControlVocabulary):
    definition = ControlVocabulary.definition # <-- Error
    class Meta:
        #...

更新：看起来这在Django中是不允许的，但我仍然在寻找解决这个问题的方法。 In Django - Model Inheritance - Does it allow you to override a parent model's attribute?

我的观点类：

class VocabulariesView(ListView):
queryset = []
template_name = 'cvinterface/index.html'

def get_context_data(self, **kwargs):
    context = super(VocabulariesView, self).get_context_data(**kwargs)
    context['vocabulary_views'] = [{'name': vocabularies[vocabulary_name]['name'], 'definition': vocabularies[vocabulary_name]['definition'], 'url': reverse(vocabulary_name)}
                                   for vocabulary_name in vocabularies]

    return context

词汇表词典的一部分：

vocabularies = {
# optional keys:
# list_view, detail_view, list_template, detail_template

'actiontype': {
    'name': ActionType._meta.verbose_name,
    'definition': ActionType._meta.definition,
    'model': ActionType,
    'detail_template': 'cvinterface/vocabularies/actiontype_detail.html',
},

Answer 1

您不必在definition中定义ActionType，因为它已经从ControlVocabulary继承了

您可以按照以下方式检查：

x = ActionType.objects.all()
x[0].__dict__

其他检查方法是查看数据库中模型的字段

编辑：

尝试复制错误：

模型：

class ControlVocabulary(models.Model):
    definition = models.TextField()
    term = models.CharField(primary_key=True, max_length=255)
    class Meta:
        abstract = True
class ActionType(ControlVocabulary):
    #definition = ControlVocabulary.definition # <-- Error
    class Meta:
        verbose_name='Action'

并在shell中：

Type "help", "copyright", "credits" or "license" for more information.
(InteractiveConsole)
>>> from testapp.models import *
>>> x = ActionType.objects.all()
>>> x
[]
>>> y = ActionType(definition='my definition')
>>> y.save()
>>> ActionType.objects.all()
[<ActionType: ActionType object>]

Django的模型继承

1 个答案: