PHP裁剪在子文件夹中找到的图像以拇指显示

时间:2015-03-10 21:04:22

标签: php echo thumbnails

我确实在某个地方找到了这个脚本,它似乎正在工作。唯一的问题是它输出的拇指尺寸与原始尺寸完全相同,即使它们被裁剪成方形......

$dir = "*/";
$images = glob($dir."main.jpg" );
echo '<div class="projects-container">'; 
foreach( $images as $image ) {
$dn = dirname($image);
$thumbsDir = $dn; // path to the thumbnails destination directory

    $imageName = "main.jpg"; // returns "cheeta.jpg"
    $thumbnail = $thumbsDir.$imageName; // thumbnail full path and name, i.e "./gallery/thumbs/cheeta.jpg"
    // for each image, get width and height
    $imageSize = getimagesize( $image ); // image size 
    $imageWidth = $imageSize[0];  // extract image width 
    $imageHeight = $imageSize[1]; // extract image height
    // set the thumb size
    if( $imageHeight > $imageWidth ){
        // images is portrait so set thumbnail width to 100px and calculate height keeping aspect ratio
        $thumbWidth = 200;
        $thumbHeight = floor( $imageHeight * ( 200 / imageWidth ) );           
        $thumbPosition  = "margin-top: -" . floor( ( $thumbHeight - 200 ) / 2 ) . "px; margin-left: 0";
    } else {
        // image is landscape so set thumbnail height to 100px and calculate width keeping aspect ratio
        $thumbHeight = 200;
        $thumbWidth = floor( $imageWidth * ( 200 / $imageHeight ) ); 
        $thumbPosition  = "margin-top: 0; margin-left: -" . floor( ( $thumbWidth - 200 ) / 2 ) . "px";
    } // END else if
    // verify if thumbnail exists, otherwise create it
    if ( !file_exists( $thumbnail ) ){
        $createFromjpeg = imagecreatefromjpeg( $image );
        $thumb_temp = imagecreatetruecolor( $thumbWidth, $thumbHeight );
        imagecopyresized( $thumb_temp, $createFromjpeg, 0, 0, 0, 0, $thumbWidth, $thumbHeight, $imageWidth, $imageHeight );
        imagejpeg( $thumb_temp, $thumbnail );
    } // END if()

echo '<div class="projects">';
echo '<div class="projects-img-container">';
echo" <a href='".$dn."'><img class='img-projet' src='". '/projects/' . $thumbnail . "'/></a>";
echo '</div>';
echo '</div>';
}
echo '</div>';
?> 

任何可能出错的想法?​​

谢谢!

2 个答案:

答案 0 :(得分:3)

你绝对没有错误处理,只是假设什么都不会出错,所以这两行:

$dir = "*/";
$image2 = imagecreatefromjpeg($dir."main.jpg");

将完全等同于

$image2 = imagecreatefromjpeg("*/main.jpg");

icfj()执行 NOT 接受通配符,句点。

由于你没有检查错误,你永远不会看到icfj()返回的布尔值为FALSE,表示失败。

答案 1 :(得分:1)

对于对这种情况的误解感到抱歉...我忘了在IMG标签中添加一些CSS样式,以便图像的位置对应于$ thumbPosition,并且对应于items-img-container div有宽度和200px的高度。

现在一切正常!