SharePoint新手。 我想以反向日期顺序从“页面”中检索项目。
这是我用来从页面获取详细信息的代码。它目前按页面顺序填充列表,但希望通过将最近添加的项目列在列表顶部来对列表进行排序。
var listTitle = "Pages";
function getEvents() {
var clientContext = new SP.ClientContext('https://int-canada.wrberkley.com/resources');
//alert("1");
var oList = clientContext.get_web().get_lists().getByTitle(listTitle);
var camlQuery = new SP.CamlQuery()
camlQuery.set_viewXml("<View></View>");
namedListItem = oList.getItems(camlQuery);
clientContext.load(namedListItem);
clientContext.executeQueryAsync(Function.createDelegate(this, this.onQuerySucceeded), Function.createDelegate(this, this.onQueryFailed));
}
function onQuerySucceeded(sender, args) {
var count = 0;
var count = namedListItem.get_count();
if (count < 1) {}
else
{
var ctrl = document.getElementById("Company Resources");
var listItemTR = "<tr><td>{1}</td><td><a href='{2}'><h2>{3}</h2></a><br />{4}</td></tr>";
var listItemInfo = "";
var listItemEnumerator = namedListItem.getEnumerator();
var CT = 0;
while (listItemEnumerator.moveNext()) {
var oListItem = listItemEnumerator.get_current();
var newsTitle = oListItem.get_item('Title');
if (newsTitle != 'Home') //Do not include "default.aspx"
{
var newsComment = oListItem.get_item('Comments');
var newsImageURL = oListItem.get_item('PublishingRollupImage');
var newsFileRef = oListItem.get_item('FileRef');
var strResult = listItemTR;
strResult = strResult.replace("{1}", newsImageURL);
strResult = strResult.replace("{2}", newsFileRef);
strResult = strResult.replace("{3}", newsTitle);
strResult = strResult.replace("{4}", newsComment);
listItemInfo += strResult;
}
CT +=1;
if (CT > 1){
break;}
}
ctrl.parentNode.innerHTML = "<table>" + listItemInfo + "</table>";
}
}
function onQueryFailed(sender, args) {
alert('Request failed. ' + args.get_message() + '\n' + args.get_stackTrace());
}
答案 0 :(得分:0)
我强烈建议您使用网站上的underscore.js样本:
//array of objects
var stooges = [{name: 'moe', age: 40}, {name: 'larry', age: 50}, {name: 'curly', age: 60}];
//underscore in action
_.sortBy(stooges, 'name');
//output
=> [{name: 'curly', age: 60}, {name: 'larry', age: 50}, {name: 'moe', age: 40}];