所以我正在创建一个Card游戏,并且一直在使用模板进行计算机科学课程。但是,没有应答键可以检查并确保我正在做的事情是正确的。所以问题是,我试图使用arraylist并交易卡,我不知道如何解决交易。我是Java的新手,所以任何帮助都将不胜感激。以下是我的代码:
public class Deck {
/**
* cards contains all the cards in the deck.
*/
private List<Card> cards;
/**
* size is the number of not-yet-dealt cards.
* Cards are dealt from the top (highest index) down.
* The next card to be dealt is at size - 1.
*/
private int size;
/**
* Creates a new <code>Deck</code> instance.<BR>
* It pairs each element of ranks with each element of suits,
* and produces one of the corresponding card.
* @param ranks is an array containing all of the card ranks.
* @param suits is an array containing all of the card suits.
* @param values is an array containing all of the card point values.
*/
public Deck(String[] ranks, String[] suits, int[] values) {
ArrayList<Card> deck = new ArrayList<Card>();
for(int a = 0; a<=ranks.length; a++){
for(int b=0; b<=suits.length;b++){
for(int c=0; c<=values.length; c++){
deck.add(new Card(ranks[a],suits[b],c));
}
}
}
}
/**
* Determines if this deck is empty (no undealt cards).
* @return true if this deck is empty, false otherwise.
*/
public boolean isEmpty() {
if(size==0){
return true;
}
else{
return false;
}
}
/**
* Accesses the number of undealt cards in this deck.
* @return the number of undealt cards in this deck.
*/
public int size() {
return size;
}
/**
* Randomly permute the given collection of cards
* and reset the size to represent the entire deck.
*/
public void shuffle() {
/* *** TO BE IMPLEMENTED IN ACTIVITY 4 *** */
}
/**
* Deals a card from this deck.
* @return the card just dealt, or null if all the cards have been
* previously dealt.
*/
public Card deal() {
while(size>0){
for(int i = 0;i<=size;i++){
return deck[i];//This cannot be resolved to the deck arraylist above
cards.remove(0);
}
}
}
/**
* Generates and returns a string representation of this deck.
* @return a string representation of this deck.
*/
@Override
public String toString() {
String rtn = "size = " + size + "\nUndealt cards: \n";
for (int k = size - 1; k >= 0; k--) {
rtn = rtn + cards.get(k);
if (k != 0) {
rtn = rtn + ", ";
}
if ((size - k) % 2 == 0) {
// Insert carriage returns so entire deck is visible on console.
rtn = rtn + "\n";
}
}
rtn = rtn + "\nDealt cards: \n";
for (int k = cards.size() - 1; k >= size; k--) {
rtn = rtn + cards.get(k);
if (k != size) {
rtn = rtn + ", ";
}
if ((k - cards.size()) % 2 == 0) {
// Insert carriage returns so entire deck is visible on console.
rtn = rtn + "\n";
}
}
rtn = rtn + "\n";
return rtn;
}
}
答案 0 :(得分:0)
尽管我还不太了解你的问题,但这可能对你有所帮助:
我检测到的一个问题是ArrayList<Card> deck
的可见性:
public Deck(String[] ranks, String[] suits, int[] values) {
ArrayList<Card> deck = new ArrayList<Card>();
...
}
由于您只在构造函数中声明ArrayList
,因此无法从外部访问列表。
所以只需将列表全局列为List<Card> cards
。然后,您可以使用deal()
方法和Deck()
构造函数访问它。
你走了:
public class Deck {
private List<Card> cards;
private int size;
private List<Card> deck;
public Deck(String[] ranks, String[] suits, int[] values) {
deck = new ArrayList<Card>();
for(int a = 0; a<=ranks.length; a++) {
for(int b=0; b<=suits.length;b++) {
for(int c=0; c<=values.length; c++) {
deck.add(new Card(ranks[a],suits[b],c));
}
}
}
}