我在php中有如下数组:
Array
(
[0] => Array
(
[id] => 1
[time] => 2014-11-09T16:32:05
[power] => 0.123
)
[1] => Array
(
[id] => 2
[time] => 2014-11-19T18:32:06
[power] => 0.208
)
[2] => Array
(
[id] => 3
[time] => 2013-09-19T20:32:07
[power] => 0.106
)
[3] => Array
(
[id] => 4
[time] => 2013-09-20T10:32:07
[power] => 0.248
)
[4] => Array
(
[id] => 5
[time] => 2013-09-20T12:32:07
[power] => 0.298
)
)
我想计算以下算法产生的每天的电力消耗:
for(i = 0; i < array.lengh - 1; i++){
$power = array.data[i].power;
$time_diff = (array.data[i+1].time)/(1000*60*60) - array.data[i].time)/(1000*60*60));
$consumption .= $power * $time_diff;
}
如何在php中执行此操作,每天对$consumption
进行分组?
答案 0 :(得分:3)
您可以在此处使用PHP强大的strtotime()
功能。这为您提供了一个unix时间戳,您可以更好地使用它。要回答您的问题,可以通过以下方式完成
$sortedData = array();
foreach ($data as $element) {
$timestamp = strtotime($element['time']);
$date = date("d.m.Y", $timestamp); //truncate hours:minutes:seconds
if ( ! isSet($sortedData[$date]) ) { //first entry of that day
$sortedData[$date] = array($element);
} else { //just push current element onto existing array
$sortedData[$date][] = $element
}
}
这应该以
的形式给你一个新的数组Array(
['19.09.2013'] => Array(
[0] => Array([id] => ..., [time] => ..., [power] => ...),
[1] => Array([id] => ..., [time] => ..., [power] => ...),
...
),
['20.09.2013'] => Array(
[0] => Array([id] => ..., [time] => ..., [power] => ...),
[1] => Array([id] => ..., [time] => ..., [power] => ...),
...
),
...
)
要获得权力的总和,只需做类似的事情
foreach ($sortedData as $date=>$elements) {
$sum = 0;
foreach ($elements as $element) {
$sum += $element['power'];
}
echo "The total sum for $date is $sum.";
}