Question

这必须是非常容易修复的东西，但由于某种原因，我无法让它工作。我一直收到错误

PLS-00201: identifier 'ART' must be declared

我的代码如下：

create or replace PROCEDURE question1(givenType IN VARCHAR, output OUT CHAR,output1 OUT CHAR)
AS
BEGIN
SELECT TITLE into output FROM CLASS where TYPE=givenType;
SELECT INSTRUCTOR into output1 FROM CLASS where TYPE=givenType;
DBMS_OUTPUT.PUT_LINE('The title of any classes with that type is: '|| output|| 'The instructor that taught each class is: ' || output1);
EXCEPTION
WHEN NO_DATA_FOUND THEN
DBMS_OUTPUT.PUT_LINE('No data found');
END;

我认为问题可能是当用户输入“艺术”时，程序将其作为“ART”并且因为我的表格类型是“Art”而不是“ART”，那么这就是我得到错误的原因。我似乎无法知道如何解决它的工作。有帮助吗？

对不起，我昨晚睡着了，这是我正在接受的完整错误

Connecting to the database CS425 Spring 2015.
ORA-06550: line 6, column 16:
PLS-00201: identifier 'ART' must be declared
ORA-06550: line 6, column 3:
PL/SQL: Statement ignored
Process exited.
Disconnecting from the database CS425 Spring 2015.

Answer 1

PLS-00201：标识符＆＃39; ART＆＃39;必须声明

我认为问题可能是当用户输入＆＃34; Art＆＃34;该计划将其作为＆＃34; ART＆＃34;因为我的桌子类型是＆＃34; Art＆＃34;不是＆＃34; ART＆＃34;那就是我收到错误的原因。

它与UPPER / LOWER案例无关。该查询被解析为：

SELECT TITLE into output FROM CLASS where TYPE=ART;

如果type是varchar类型，则必须将值作为字符串传递，即必须将其括在单引号中。否则，Oracle会将其解释为标识符。所以，它应该是：

SELECT TITLE into output FROM CLASS where TYPE='ART';

例如，

SQL> SET SERVEROUTPUT ON
SQL> DECLARE
  2    o_dept NUMBER;
  3  BEGIN
  4    SELECT DEPTNO INTO o_dept FROM EMP WHERE ENAME=SCOTT;
  5    dbms_output.put_line(o_dept);
  6  END;
  7  /
  SELECT DEPTNO INTO o_dept FROM EMP WHERE ENAME=SCOTT;
                                                 *
ERROR at line 4:
ORA-06550: line 4, column 50:
PL/SQL: ORA-00904: "SCOTT": invalid identifier
ORA-06550: line 4, column 3:
PL/SQL: SQL Statement ignored


SQL> DECLARE
  2    o_dept NUMBER;
  3  BEGIN
  4    SELECT DEPTNO INTO o_dept FROM EMP WHERE ENAME='SCOTT';
  5    dbms_output.put_line(o_dept);
  6  END;
  7  /
20

PL/SQL procedure successfully completed.

SQL>

而且，使用保留关键字作为对象名称并不是一个好主意。 TYPE是保留关键字。

必须声明PLS-00201标识符

1 个答案: