我想将带有下划线大小写的json变换为驼峰大小写。
"{\"first_key\": \"first_value\", \"second_key\": {\"second_first_key\":\"second_first_value\"}}"
到
"{\"firstKey\": \"first_value\", \"secondKey\": {\"secondFirstKey\":\"second_first_value\"}}"
这是部分代码:
val CamelCaseRegex = new Regex("(_.)")
val jsonTransformer = (__).json.update(
//converts json camel_case field names to Scala camelCase field names
)
val jsonRet = Json.parse(jsonStr).transform(jsonTransformer)
我在更新方法中尝试了几种方法但没有成功。
答案 0 :(得分:2)
虽然只使用原生Play库来做这件事会很好,但对于Mandubian的Play Json Zipper扩展库来说,这是一个很好的用例。
这是一个快速的解决方案(没有经过详尽的测试)。首先,您需要将解析器和库添加到构建中:
resolvers += "mandubian maven bintray" at "http://dl.bintray.com/mandubian/maven"
libraryDependencies ++= Seq(
"com.mandubian" %% "play-json-zipper" % "1.2"
)
然后你可以尝试这样的事情:
import play.api.libs.json._
import play.api.libs.json.extensions._
// conversion function borrowed from here:
// https://gist.github.com/sidharthkuruvila/3154845
def underscoreToCamel(name: String) = "_([a-z\\d])".r.replaceAllIn(name, {m =>
m.group(1).toUpperCase
})
// Update the key, otherwise ignore them...
// FIXME: The None case shouldn't happen here so maybe we
// don't need it...
def underscoreToCamelCaseJs(json: JsValue) = json.updateAllKeyNodes {
case (path, js) => JsPathExtension.hasKey(path) match {
case Some(key) => underscoreToCamel(key) -> js
case None => path.toJsonString -> js
}
}
关于此输入:
val testJson = Json.obj(
"some_str" -> JsString("foo_bar"),
"some_obj" -> Json.obj(
"some_field" -> Json.arr("foo", "bar")
),
"an_int" -> JsNumber(1)
)
...生产:
{
"someStr" : "foo_bar",
"someObj" : {
"someField" : [ "foo", "bar" ]
},
"anInt" : 1
}
答案 1 :(得分:2)
根据您的要求,您可以使用此库 play-json-naming 。它可以轻松地将snake_case
(下划线情况)json转换为camelCase
,反之亦然。
https://github.com/tototoshi/play-json-naming
答案 2 :(得分:0)
如果您使用播放> = 2.6:
final case class Blah(foo: String)
object Blah {
import play.api.libs.json._
implicit val config = JsonConfiguration(SnakeCase)
implicit val blahReader:OFormat[QueueMsgEnvelope] = Json.format[Blah]
}