Question

我正在为一个康威的生命游戏程序进行上课..下面的方法读取一个指定的输入文件，将其读入一个int数组，并返回该数组..

import java.util.*;
import java.io.*;

public class Proj5 {
public static void main(String[] args) throws IOException   {
//the main method controls the flow of the program
    String filename = args[0];
    int[][] cells = readBoard(filename);

    for (int i = 0; i < cells.length; i++)  {
        for (int j = 0; j < cells[i].length; j++)   {
            System.out.print(cells[i][j]);
        }
        System.out.println("");
    }

}

public static int[][] readBoard(String filename) throws IOException {
// This method reads the specified input file, reads it into an int[][] array, and returns that array.
    Scanner inFile = new Scanner(new File(filename));
    int row = Integer.parseInt(inFile.nextLine());
    int col = Integer.parseInt(inFile.nextLine());

    int[][] cells = new int[row][col];

    inFile.nextLine();
    for (int i = 0; i < row; i++)   {
        for (int j = 0; j < col; j++)   {
            cells[i][j] = inFile.nextInt();
        }
        inFile.nextLine();
    }

    inFile.close();
    return cells;
}

扫描程序读取的文本文件的格式如下所示..其中顶行是行数，第二行是列数，其余是需要放入数组的数据：

25
77
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000001110000000000000000000000000000000000000000000000000000000
00000000000000001110001110000000000000000000000000111110000000000000000000000
00000000000000111100000111100000000000000000001111100011111000000000000000000
00000000000000001110001110000000000000000000000000111110000000000000000000000
00000000000000000001110000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000001110000000000000000000000000000000000000000000000000000000
00000000000000001110001110000000000000000000000000111110000000000000000000000
00000000000000111100000111100000000000000000001111100011111000000000000000000
00000000000000001110001110000000000000000000000000111110000000000000000000000
00000000000000000001110000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000

然而，当我正在运行我的程序时...我正在接受：

线程“main”中的异常java.util.InputMismatchException：对于输入字符串：“00000000000000000001110000000000000000000000000000000000000000000000000000000” 在java.util.Scanner.nextInt（未知来源）

at java.util.Scanner.nextInt（unknown source）

在Proj5.readBoard（Proj5.java:30）

在Proj5.main（Proj5.java:8）

并且我不完全确定为什么或如何解决它......

Answer 1

使用nextInt()将尝试将每个文件行转换为单个整数。

抛出异常，因为被视为单个数字的整行不符合int值。

我要解决此问题的方法是每行使用一次readLine次调用来消耗整行输入。然后使用charAt String方法检查该行特定列的字符。如有必要，可以通过减去int的值有效地将其转换为'0'。

康威生命游戏中的物品不匹配例外

1 个答案: