Question

我有一个SQL查询输出，如下所示

Customer  LastModifiedDate

A          1/12/2013
B          1/1/2015
C          1/28/2015

现在，我需要显示客户计数，其详细信息在(30-60 days)，(61-90 Days)和90+等不同日期更新（超过90天）例如，请参阅下面的输出

DaysRange      CustomersCount

30-60          1
61-90          1
90+            1

请帮助我实现上述输出

Answer 1

像这样。

SELECT DaysRange=CASE
                   WHEN Datediff(DAY, LastModifiedDate, Getdate()) BETWEEN 30 AND 60 THEN '30-60'
                   WHEN Datediff(DAY, LastModifiedDate, Getdate()) BETWEEN 61 AND 90 THEN '61-90'
                   WHEN Datediff(DAY, LastModifiedDate, Getdate()) > 90 THEN '90+'
                 END,
       CustomersCount=Count(1)
FROM   yourtable
GROUP  BY CASE
            WHEN Datediff(DAY, LastModifiedDate, Getdate()) BETWEEN 30 AND 60 THEN '30-60'
            WHEN Datediff(DAY, LastModifiedDate, Getdate()) BETWEEN 61 AND 90 THEN '61-90'
            WHEN Datediff(DAY, LastModifiedDate, Getdate()) > 90 THEN '90+'
          END

Answer 2

使用此查询：

SELECT COUNT(CASE WHEN DATEDIFF(d, LastModifiedDate, getdate()) BETWEEN 30 AND 60 THEN 1 END) AS [30-60],
       COUNT(CASE WHEN DATEDIFF(d, LastModifiedDate, getdate()) BETWEEN 61 AND 90 THEN 1 end) AS [61-90],
       COUNT(CASE WHEN DATEDIFF(d, LastModifiedDate, getdate()) > 90 THEN 1 END) AS [90+]
   FROM mytable

产生以下输出：

30-60   61-90   90+
1       1       1

使用UNPIVOT，我们可以获得所需的结果集：

SELECT DaysRange, CustomersCount
FROM (
   SELECT COUNT(CASE WHEN DATEDIFF(d, LastModifiedDate, getdate()) BETWEEN 30 AND 60 THEN 1 END) AS [30-60],
          COUNT(CASE WHEN DATEDIFF(d, LastModifiedDate, getdate()) BETWEEN  61 AND 90 THEN 1 END) AS [61-90],
          COUNT(CASE WHEN DATEDIFF(d, LastModifiedDate, getdate()) > 90 THEN 1 END) AS [90+]
   FROM mytable) p
UNPIVOT
   (CustomersCount FOR DaysRange IN ([30-60], [61-90], [90+])
) AS unpvt;

<强>输出：

DaysRange   CustomersCount
30-60       1
61-90       1
90+         1

以天数范围显示数据

2 个答案: