Question

我正在使用Google财经的PHP和JSON来获取实时股票更新/报价 http://finance.google.com/finance/info?client=ig&q=GOOG（这只是一个例子）我的代码与上面提到的链接一起工作正常（因为它只有一个我想要获得的股票，即GOOG）但如果我尝试在最后添加更多的股票代码

{
    <?php                                                   
        <?php $url="http://finance.google.com/finance/info?client=ig&q=GOOG,AAPL,MAC "
         /* (here I'm trying to get data for 3 stocks (i.e GOOG, AAPL, MAC) 
         it generates the JSON but I'm unable to change it into proper Array.*/          
              $g_f_data= file_get_contents($url);
              $json = str_replace("\n", "", $g_f_data);
              $data = substr($json, 4, strlen($json) -5);

              $json_output = json_decode($data, true);
              echo"<pre>";
              print_r ($json_output);
              echo"</pre>";
             echo $json_output['t'],$json_output['l'],$json_output['cp'];echo "<br />"; 
    ?>
}

Answer 1

<?php 

$url="http://finance.google.com/finance/info?client=ig&q=GOOG,AAPL,MAC";

$quote= file_get_contents($url);

$json = str_replace("\n", "", $quote); //clean
$data = substr($json, 4, strlen($json) -5); 
$json_output = json_decode($data, true);  
echo '<pre>';
print_r($json_output);

Answer 2

您必须删除＆＃39; //＆＃39;来自Google的respoce。

$quote= file_get_contents($url);

$json = str_replace('// [', ' [', $quote);
$data = substr($json, 4, strlen($json) -5); 
$results = json_decode($quote, true);
echo '<pre>';
print_r($results);

Google财经JSON不支持超过1个符号

2 个答案: