Question

使用Ansible原始模块获取mysql请求的正确方法是什么？

ansible host -m raw -a 'mysql mydb -e "SELECT lastname FROM table WHERE fistname = 'Joe'"' --su -vvvv

这不起作用，并给我以下输出

<host> 
<host> PubkeyAuthentication=no ConnectTimeout=10 'su  root -c "$SHELL -c '"'"'echo SUDO-SUCCESS-sbqanpltaxkqfzxjdnpjytpnytyhrvow; mysql mydb -e "SELECT lastname FROM table WHERE firstname=Joe"'"'"'"' GSSAPIAuthentication=no User=user ControlPath=/home/user/.ansible/cp/ansible-ssh-%h-%p-%r ControlMaster=auto ControlPersist=60s
host | FAILED | rc=1 >>

value: -c: line 0: unexpected EOF while looking for matching `''
value: -c: line 1: syntax error: unexpected end of file
debug3: mux_client_read_packet: read header failed: Broken pipe
debug2: Received exit status from master 1
Shared connection to host closed.


ERROR 1054 (42S22) at line 1: Unknown column 'firstname' in 'where clause'

然后如果我试图逃跑：

ansible host -m raw -a 'mysql mydb -e \"SELECT lastname FROM table WHERE fistname = 'Joe'\"'

Ansible删除命令中的单引号，给出此输出：

<host> 
<host> PubkeyAuthentication=no ConnectTimeout=10 GSSAPIAuthentication=no   User=user 'su  root -c "$SHELL -c '"'"'echo SUDO-SUCCESS-dmbzdeiqiygmuoebxlswxfzdaxxutgqp; mysql mydb -e \"SELECT value FROM table WHERE firstname=Joe\"'"'"'"' ControlPath=/home/user/.ansible/cp/ansible-ssh-%h-%p-%r ControlMaster=auto ControlPersist=60s
host | FAILED | rc=1 >>
ERROR 1054 (42S22) at line 1: Unknown column 'firstname' in 'where clause'
debug3: mux_client_read_packet: read header failed: Broken pipe
debug2: Received exit status from master 1
Shared connection to host closed.

Answer 1

根据Ansible文档，the raw module用于执行“低 - 低且脏的SSH命令”，并且只应在几个非常特殊的情况下使用。根据文档所述，您根本不应该使用此模块来尝试调用mysql。

您可能想要做的是使用command（或shell）模块：

$ ansible -i ./hosts localhost -m command -a 'mysql -u user -ppass -h mydbhost -e "show databases"'

我刚试过这个，它按预期工作。

Ansible raw＆amp;引用

1 个答案: