Question

在尝试基于过滤器执行流媒体推文的代码时，我得到了下面提到的错误。

Traceback (most recent call last):   
    File "new5.py", line 37, in <module> stream.filter(track=[sys.argv[1]])   
    File "/usr/lib/python2.6/site-packages/tweepy/streaming.py", line 428, in filter self._start(async)   
    File "/usr/lib/python2.6/site-packages/tweepy/streaming.py", line 346, in _start self._run()   File "/usr/lib/python2.6/site-packages/tweepy/streaming.py", line 239, in _run verify=self.verify)   
    File "/usr/lib/python2.6/site-packages/requests/sessions.py", line 461, in request resp = self.send(prep, **send_kwargs) 
    File "/usr/lib/python2.6/site-packages/requests/sessions.py", line 573, in send r = adapter.send(request, **kwargs)   
    File "/usr/lib/python2.6/site-packages/requests/adapters.py", line 415, in send raise ConnectionError(err, request=request) requests.exceptions.ConnectionError: ('Connection aborted.', error(111, 'Connection refused'))

请在下面找到我使用的代码。

from tweepy.streaming import StreamListener
from tweepy import OAuthHandler
from tweepy import Stream
import sys
import json

consumer_key = ""
consumer_secret = ""
access_token = ""
access_token_secret = ""


class StdOutListener(StreamListener):

    def on_data(self, data):
        print('tweet: ' + json.loads(data)['text'])
        return True

    def on_error(self, status):
        print(status)

if __name__ == '__main__':
    if len(sys.argv) < 2:
        print("Usage: python %s filter_name" % sys.argv[0])
        sys.exit(1)
    l = StdOutListener()
    auth = OAuthHandler(consumer_key, consumer_secret)
    auth.set_access_token(access_token, access_token_secret)

    stream = Stream(auth, l)
    stream.filter(track=[sys.argv[1]])

我在CentOS6.3上使用python 2.6.6

Answer 1

问题是您的代理连接失败并且tweepy没有代理支持。您可以使用内置代理支持的twitterAPI或查看this。它是一个带有代理实现的tweepy fork

使用python 2.6.6传输推文时出现连接错误

1 个答案: