注意:尝试在C:\ xampp \ htdocs \ myhost中获取非对象的属性

时间:2015-03-09 08:49:47

标签: php mysqli

我试图通过PHP脚本获取用户凭据,但我强迫一个问题。源代码是

    <?php
    include 'utilities.php'; 
    $conn = openDB();
    $table = "customer"; 
    $username = $_POST['username'];
    $pwd = $_POST['pwd']; 


    $sql = "SELECT * FROM $table WHERE username = '{$username}' and pwd = '{$pwd}' ";
    $result = $conn->query($sql);
    if($result->num_rows > 0)// here is line 12
{

    echo "<br /> Successfully logged in as $username";
    if ($username == "admin")
    echo "<a href='Administrator.html'>Administrator</a>";  
    else
    echo "<a href = 'UserMenu.html'>UserMenu</a>";

}
    else

{

    echo "<br /> Invalid Login";


}
   $conn->close();


   ?>

和错误是

成功连接

注意:尝试在

中获取非对象的属性 第12行的

C:\ xampp \ htdocs \ myhost \ ProcessLogin.php

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0 个答案:

没有答案