Question

这是从GBA4iOS控制器视图中逐字逐句改变振动长度的几行代码：

void AudioServicesStopSystemSound(int);
void AudioServicesPlaySystemSoundWithVibration(int, id, NSDictionary *);

@implementation vibeObject;

- (void)vibrate
{
    AudioServicesStopSystemSound(kSystemSoundID_Vibrate);

    int64_t vibrationLength = 30;

    NSArray *pattern = @[@NO, @0, @YES, @(vibrationLength)];

    NSMutableDictionary *dictionary = [NSMutableDictionary dictionary];
    dictionary[@"VibePattern"] = pattern;
    dictionary[@"Intensity"] = @1;

    AudioServicesPlaySystemSoundWithVibration(kSystemSoundID_Vibrate, nil, dictionary);
}

@end

我在这里的尝试只是拒绝在所有情况下工作：

func AudioServicesStopSystemSound(Int);
func AudioServicesPlaySystemSoundWithVibration(Int , NilLiteralConvertible, NSDictionary)();

func vibrate(){

    AudioServicesStopSystemSound(kSystemSoundID_Vibrate);

    let vibrationLength = 30;

    let pattern: NSArray = [false, 0, true, vibrationLength];

    var dictionary:NSMutableDictionary;
    dictionary["VibePattern"] = pattern;
    dictionary["Intensity"] = 1;

    AudioServicesPlaySystemSoundWithVibration(kSystemSoundID_Vibrate, nil, dictionary);
}

当取消注释时，它会崩溃SourceKit，但只会在视图控制器中崩溃。当我把它放在自己的文件中时：

vibeObject.vibrate(<# RIGHT HERE IT TELLS ME "EXPECTED ',' SEPARATOR vibeObject#>);

我已尽力而为，如果你能提供帮助，我将非常感激

Answer 1

在＆＃34; AudioServicesPlaySystemSoundWithVibration＆＃34;之后删除一组括号。声明。

自：

func AudioServicesPlaySystemSoundWithVibration(Int , NilLiteralConvertible, NSDictionary)();

要：

func AudioServicesPlaySystemSoundWithVibration(Int , NilLiteralConvertible, NSDictionary);

Answer 2

首先，您不需要函数声明。（事实上，我并不确定它是否有效。）

这一行：

 var dictionary:NSMutableDictionary;

不创建可变字典，需要写：

var dictionary = NSMutableDictionary()

如何将这个Objective-c代码片段写入Swift？

2 个答案: