我遇到了以下问题,想要添加查询结果" id"作为价值的关键" concat" - 我需要一个foreach吗?什么是最好的方式?
$concatCol = mysqli_query( $connS, "SELECT id, ShipmentNumber, InvoiceNumber, BillofLading from testTable");
$data =array();
while ($row = mysqli_fetch_array($concatCol)) {
$id = $row["id"];
$ShipmentNumber = $row["ShipmentNumber"];
$InvoiceNumber = $row["InvoiceNumber"];
$BillofLading = $row["BillofLading"];
$concat = $ShipmentNumber.$InvoiceNumber.$BillofLading;
echo $concat."<br>";
$data[] = $concat;
}
答案 0 :(得分:0)
我不确定你的预期输出是多少。但我认为以下其中一项对您有用:
$data[]['id'] = $concat;
将生成如下数组:
Array
(
[0] => Array
(
[id] => ShipmentNumberInvoiceNumberBillofLanding
)
[1] => Array
(
[id] => ShipmentNumberInvoiceNumberBillofLanding
)
)
第二个选项是:
$data[$id] = $concat;
将产生如下结果:
Array
(
[1] => ShipmentNumberInvoiceNumberBillofLanding
[4] => ShipmentNumberInvoiceNumberBillofLanding
)
每个返回行的密钥1
和4
都是$id
。在这两个示例中,ShipmentNumberInvoiceNumberBillofLanding
当然是每行的连接值。